The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. (a) Find the mass (in mg) that remains after t years.

1 answer:

4 0

The half-life of cesium-137 is 30 years. Suppose we have a 150 mg sample. The masses (in mg) that remains after t years A=150/2^t/30yrs

A substance's half-life is the amount of time it takes for half of it to decompose.

<h3>What is a half-life example?</h3>

Half-life is the length of time it takes for half of an unstable nucleus to go through its decay process. A radioactive element's half-life decay time varies depending on the element. For instance, carbon-10 has a half-life of only 19 seconds, making it impossible to discover in nature. On the other hand, uranium-233 has a half-life of almost 160000 years.

When n half-lives have passed, the formula for estimating the amount still left is:-

A=A°/2^n

where,

A=initial amount

A°=remaining amount

n=t/t_{1/2}

A=150/2^t/30yrs

Learn more about half-life here:-

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4 years ago

A sample of carbon dioxide gas occupies a volume of 250 mL at 25c what volume will it occupy at 95c

anzhelika [568]

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<h3>Charles's law</h3>

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.

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$\frac{V}{T} =k$