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SpyIntel [72]
3 years ago
7

In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq

Chemistry
2 answers:
mariarad [96]3 years ago
5 0
Assuming that the reactants are:

(NH4)2SO4 (aq) + Ba(NO3)2 (aq)

and the products are:

BaSO4 (s) + 2NH4NO3 (aq),

then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.

According to the solubility rules, the following elements are considered insoluble when paired with SO4:

Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+

Therefore, the precipitate will be BaSO4 (s).

Mkey [24]3 years ago
5 0

Answer:

The precipitate is BaSO₄.

Explanation:

A precipitate is a chemical substance that in a liquid solution is in solid phase.

In the reaction:

(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) → BaSO₄(s) + 2NH₄NO₃(aq)

(NH₄)₂SO₄, Ba(NO₃)₂ and NH₄NO₃ are in aqueous solution <em>(aq) </em>while BaSO₄ is in solid phase <em>(s)</em>, that means that the <em>precipitate is BaSO₄</em>

<em></em>

I hope it helps!

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The mole fraction of iodine, i2, dissolved in dichloromethane, ch2cl2, is 0.115. what is the molal concentration, m, of iodine i
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The molality of a solute is equal to the moles of solute per kg of solvent. We are given the mole fraction of I₂ in CH₂Cl₂ is <em>X</em> = 0.115. If we can an arbitrary sample of 1 mole of solution, we will have:

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