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SpyIntel [72]
3 years ago
7

In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq

Chemistry
2 answers:
mariarad [96]3 years ago
5 0
Assuming that the reactants are:

(NH4)2SO4 (aq) + Ba(NO3)2 (aq)

and the products are:

BaSO4 (s) + 2NH4NO3 (aq),

then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.

According to the solubility rules, the following elements are considered insoluble when paired with SO4:

Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+

Therefore, the precipitate will be BaSO4 (s).

Mkey [24]3 years ago
5 0

Answer:

The precipitate is BaSO₄.

Explanation:

A precipitate is a chemical substance that in a liquid solution is in solid phase.

In the reaction:

(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) → BaSO₄(s) + 2NH₄NO₃(aq)

(NH₄)₂SO₄, Ba(NO₃)₂ and NH₄NO₃ are in aqueous solution <em>(aq) </em>while BaSO₄ is in solid phase <em>(s)</em>, that means that the <em>precipitate is BaSO₄</em>

<em></em>

I hope it helps!

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Taking into account the reaction stoichiometry, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The following rule of three can be applied: If by stoichiometric reaction 1 mole of Ca(OH)₂ is produced by 1 mole of CaO, 2 moles of Ca(OH)₂ are produced by how many moles of CaO?

moles of CaO=\frac{2 moles of Ca(OH)_{2}x1 mol of CaO }{1 mole of Ca(OH)_{2}}

moles of CaO= 2 moles

Finally, 2 moles of CaO are required to react with 2 moles of Ca(OH)₂.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

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