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SpyIntel [72]
3 years ago
7

In the following reaction, which substance is the precipitate? (NH4)2SO4(aq) + Ba(NO3)2(aq) BaSO4(s) + 2NH4NO3(aq

Chemistry
2 answers:
mariarad [96]3 years ago
5 0
Assuming that the reactants are:

(NH4)2SO4 (aq) + Ba(NO3)2 (aq)

and the products are:

BaSO4 (s) + 2NH4NO3 (aq),

then you will have to determine which product is insoluble. You should have access to solubility rules to help you determine this.

According to the solubility rules, the following elements are considered insoluble when paired with SO4:

Sr^2+, Ba^2+, Pb^2+, Ag^2+, and Ca^2+

Therefore, the precipitate will be BaSO4 (s).

Mkey [24]3 years ago
5 0

Answer:

The precipitate is BaSO₄.

Explanation:

A precipitate is a chemical substance that in a liquid solution is in solid phase.

In the reaction:

(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) → BaSO₄(s) + 2NH₄NO₃(aq)

(NH₄)₂SO₄, Ba(NO₃)₂ and NH₄NO₃ are in aqueous solution <em>(aq) </em>while BaSO₄ is in solid phase <em>(s)</em>, that means that the <em>precipitate is BaSO₄</em>

<em></em>

I hope it helps!

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Ammonia, NH3; ammonium nitrate, NH4NO3; and ammonium hydrogen phosphate, (NH4)2HPO4, are all common fertilizers. Rank the compou
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Mass percentage -

Mass percentage of A is given as , the mass of the substance A by mass of the total solution multiplied by 100.

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Given,  

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1. Ammonia, NH₃

Hence , the mass of solution is calculated as the summation of the mass of the atom * number of atom ,  

Hence ,  

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mass % N = mass of N / mass of solution * 100

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mass % N = mass of N / mass of solution * 100

mass % N = 14 g/mol / 80 g/mol * 100

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Hence , the mass of solution is calculated as the summation of the mass of the atom * number of atom ,  

Hence ,  

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and ,

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The mass percent of nitrogen can be calculated from using the above formula  

mass % N = mass of N / mass of solution * 100

mass % N = 14 g/mol / 132 g/mol * 100

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Hence , the correct order is -

Ammonia, NH₃ > ammonium nitrate, NH₄NO₃ > ammonium hydrogen phosphate, (NH₄)₂HPO₄

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