The major changes in the state of the universe that occurred immediately after the Big Bang were in ______ and _____

Derivation of Eq. (3): o Basic physics principles: Justify equations (1) and (2) in your own words. . Doing the algebra: From eq

zysi [14]

Answer:

About eq (1)

$mv^2/r = eVB$

when a charged particle (electron) enters into the magnetic field which is perpendicular to direction of motion than there will be magnetic force on particle and particle will travel in circular path in with constant speed.

So using force balance on charged particle:

$F_{net} = Fc - Fm$

Since particle is traveling at constant speed, So acceleration is zero, and

$F_{net} = 0$

$Fc - Fm=0$

$Fc = Fm$

Fc = centripetal force on particle $= m*v^2/r$

Fm = magnetic force on electron = $q*VxB = q*V*B*sin \theta$

q = charge on electron = e

since magnetic field is perpendicular to the velocity of particle, So theta = 90 deg

sin 90 deg = 1

So,

$m*v^2/r = e*v*B$

About equation 2:

When this charged particle is released from rest in a potential difference V, and then it enters into above magnetic field, then using energy conservation on charge particle

$KEi + PEi = KEf + PEf$

KEi = 0, since charged particle started from rest

$PEi - PEf = q*dV$

$PEi - PEf = eV$

KEf = final kinetic energy of particle when it leaves $= (1/2)*m*v^2$

So,

$0 + eV = (1/2)*m*v^2$

$eV = (1/2)*m*v^2$

From above equation (1) and (2)

$m*v^2/r = evB$

$e/m = v/(r*B)$

Now

$eV = (1/2)*m*v^2$

$v = \sqrt{(2*e*V/m)}$

$e/m = \sqrt{ (2*e*V/m)/(r*B)}$

$\frac{e^2}{m^2} = \frac{2*e*V}{(m*r^2*B^2)}$

$e/m = 2*V/(r^2*B^2)$

$e/m = 2V/(Br)^2$

7 0

3 years ago

I need help with this

Vilka [71]

The right answer is atom. Please rate brainiest.

3 0

3 years ago

In diving to a depth of 308 m, an elephant seal also moves 579 m due east of his starting point. What is the magnitude of the se

Kisachek [45]

Answer:

655.82m

Explanation:

By tracing the distances traveled from 308m down in the water and then 579m to the east, a <u>right triangle </u>can be formed and the displacement can be found by the Pythagorean theorem. This is shown in the attached image (the red line is the displacement).

One leg of the triangle will be the 308m

and the second leg of the triangle will be the 579m.

If we call the displacement $x$ , by the pythagorean theorem: