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3 years ago

What is the slope of the line passing through the points (2,−5) and (4, 1)?

Physics

2 answers:

sergij07 [2.7K]3 years ago

5 0

I hope this helps you

Arisa [49]3 years ago

5 0

Hope this helps :)

The bottom picture solves it

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Solnce55 [7]

Answer:

The answer would be d because of were the bolt is it has to reset after using it.

8 0

3 years ago

A fluid in an aquifer is 23.6 m above a reference datum, the fluid pressure (in gage pressure) is 4390 n/m2 and the flow velocit

Phoenix [80]

As per Bernuolli's Theorem total energy per unit mass is given as

$\frac{P}{\rho} + \frac{1}{2}v^2 + gH = E$

now from above equation

$P = 4390 N/m^2$

$\rho = 0.999 * 10^3$

$v = 7.22 * 10^{-4} m/s$

$H = 23.6 m$

now by above equation

$\frac{4390}{0.999*10^3} + \frac{1}{2}*(7.22*10^{-4})^2 + 9.8*23.6 = E$

$E = 235.7 J/kg$

Part B)

Now energy per unit weight

$U = \frac{E}{g}$

$U = \frac{235.7}{9.8}$

$U = 24 m$

7 0

3 years ago

Two technicians are discussing electronic leveling systems. Technician A says that a weight should be placed in the vehicle as p

Ronch [10]

Answer:

C. Both A and B

Explanation:

<em>Electronic leveling systems: </em>These are automatic lifting jacks use for raising wheels and vehicle when parked or when work is to be done on the vehicle engine underneath or on wheels. unlike the manual jacks it is very quick and efficient.

Both technician right, for Technician A, a weight may be use during the procedure for balancing and leveling when raising, and for Technician B, the sensor in the electronic leveling systems is adjustable to adjust the height so as to maintain balancing and levelling.

8 0

3 years ago

A marble runs off the edge of a table that is 1.5 m high and the marble lands 0.50 m from the base of the table. a. How much tim

Free_Kalibri [48]

Answer:

t = 0.55[sg]; v = 0.9[m/s]

Explanation:

In order to solve this problem we must establish the initial conditions with which we can work.

y = initial elevation = - 1.5 [m]

x = landing distance = 0.5 [m]

We set "y" with a negative value, as this height is below the table level.

in the following equation (vy)o is equal to zero because there is no velocity in the y component.

therefore:

$y = (v_{y})_{o}*t - \frac{1}{2} *g*t^{2}\\ where:\\(v_{y})_{o}=0[m/s]\\t = time [sg]\\g = gravity = 9.81[\frac{m}{s^{2}}]\\ -1.5 = 0*t -4.905*t^{2} \\t = \sqrt{\frac{1.5}{4.905} } \\t=0.55[s]$

Now we can find the initial velocity, It is important to note that the initial velocity has velocity components only in the x-axis.

$(v_{x} )_{o} = \frac{x}{t} \\(v_{x} )_{o} = \frac{0.5}{0.55} \\(v_{x} )_{o} =0.9[m/s]$

3 0

3 years ago

If 2 people are on a bed and they are the same weight, and 1 of them gets off and the bed breaks who is responsible? Is it the p

alekssr [168]

Answer:

I would say the one who got up bc if he or she wouldn't have gotten up the bed wouldn't have broke

6 0

3 years ago