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melamori03 [73]
3 years ago
9

the expression like a ton of bricks means very hard would being hit by an actual ton of brick ls hurt?

Physics
1 answer:
Olegator [25]3 years ago
8 0

Answer:

well bricks are heavy so yeah i guess so if you have a ton of them dropped on you lol

Explanation:

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A 3.00 kg mass is traveling at an initial speed of 25.0 m/s. What is the
Nitella [24]

Answer:

The magnitude of the force required to bring the mass to rest is 15 N.

Explanation:

Given;

mass, m = 3 .00 kg

initial speed of the mass, u = 25 m/s

distance traveled by the mass, d = 62.5 m

The acceleration of the mass is given as;

v² = u² + 2ad

at the maximum distance of 62.5 m, the final velocity of the mass = 0

0 = u² + 2ad

-2ad = u²

-a = u²/2d

-a = (25)² / (2 x 62.5)

-a = 5

a = -5 m/s²

the magnitude of the acceleration = 5 m/s²

Apply Newton's second law of motion;

F = ma

F = 3 x 5

F = 15 N

Therefore, the magnitude of the force required to bring the mass to rest is 15 N.

4 0
3 years ago
How is current related to voltage? ​
Tju [1.3M]

The relationship between current and voltage and resistance is described by ohlm's law. This equation i=v/r tells that the current i flowing through a circuit is directly proportional to the voltage v, and inversely proportional to resistance r. This desceibes the relationship of voltage, current and resistance.

8 0
3 years ago
Read 2 more answers
A nonconducting spherical shell, with an inner radius of 4 cm and an outer radius of 6 cm, has charge spread nonuniformly throug
Vaselesa [24]

Answer:

1.57 * 10^{3} Q

Explanation:

The volume charge density is defined by ρ = \frac{Q}{V} (Equation A), where Q is the charge and V, the volume.

The units in the S.I. are \frac{Coulombs}{m^{3} }, so we have to express the radius in meters:

inner radius = 4 cm * \frac{1 m}{100 cm} = 0.04m

outer radius = 6 cm * \frac{1m}{100cm}  = 0.06m

Now, we know that the volume of the sphere is calculated by the formula:

V = \frac{4}{3}\pi r^{3}, and as we have an spherical shell, the volume is calculated by the difference between the outher and inner spheres:

V = \frac{4}{3}\pi (r_{o} ^{3} - r_{i} ^{3}), where r_{o} is the outer radius and r_{i} is the inner radius.

Replacing the volume formula in the Equation A:

ρ = \frac{Q}{\frac{4}{3}\pi(r^{3} _{o}-r_{i} ^{3})}

ρ = \frac{3Q}{4\pi (r_{o} ^{3}-r_{i} ^{3} ) }

Replacing the values of the outer and inner radius whe have:

ρ = \frac{3Q}{4\pi (1.52 * 10^{-4})}

ρ = 1.57 * 10^{3} Q

4 0
3 years ago
At the instant the traffic light turns green, a car that has been waiting at an intersection starts with a constant acceleration
Setler79 [48]

Answer:

(a) 300 ft

(b) 60 ft/s

Explanation:

distance d=0.5at^{2} where a is acceleration and t is time

d=0.5\times 6\times t^{2}=3t^{2}

Also, d=vt where v is the velocity

d=30t

Therefore

30t=3t^{2} hence t=10 s

Substituting t is either formula

d=30t=30*10=300 ft

Also

v=at hence v=6\times 10=60 ft/s

4 0
2 years ago
A force of 6 N acts on a 33 kg object for 9 seconds. What is the objects change in velocity?
GuDViN [60]
Acceleration = change in velocity/time
By F = ma,
6 = 33 x change in velocity / 9
change in velocity = +1.636 m/s
4 0
3 years ago
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