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podryga [215]
2 years ago
12

Please help I don’t know this question )): thank you !!(:p

Chemistry
1 answer:
alekssr [168]2 years ago
8 0

\fbox{ \sf Correct \:  answer \:  is  \: +1}

The given data states that the 2-D diagram is representing Lithium molecule.

few things one must know before solving the question,

Lithium is a Alkali metal having 3 electrons, out of which two electrons lies in 1S orbital (K shell) & one electron lies in 2S orbital. To attain the stability ( nobel configuration) lithium requires 7 electron which is not possible at ordinary condition & it requires a huge amount of energy instead lithium loses one electron from outermost shell.

We know that when any atom loses a electron the oxidation number is written with plus(+) symbol.

Hence net charge on lithium ion is +1

\small \sf Thanks  \: for  \: joining \:  brainly \:  community! \:

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It takes 93.75 mL of a 0.200 M NaOH to neutralize 75.0 mL of an unknown
borishaifa [10]

Answer:

the answer is the second option

5 0
2 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
What is the mass in grams of 2.0 moles of NO2
JulsSmile [24]
Molar mass NO₂ = 46.0 g/mol

1 mole -------- 46.0 g
2.0 moles ----- ?

Mass (NO₂) = 2.0 x 46.0 / 1

=> 92.0 g

hope this helps!
8 0
3 years ago
Read 2 more answers
Which model of the atom is the most accurate
Zarrin [17]
Quantum Mechanical model (as per my knowledge)
7 0
3 years ago
What is the percent composition by mass of each element in Co(HSO4)2?
MrRissso [65]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

Molecular formula for calcium hydroxide is Ca(OH)₂

As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

1 mol of hydroxide weighs 74.08 g

1 mol of hydroxide has 1 mol of Ca, therefore 40.08 g are Ca

2 moles of O therefore 32g are O

2 moles of H therefore 2 g are H

Percentage composition is known as (Mass of element/Total mass) . 100

(40.08 / 74.08) . 100 = 54.1 %

(32 / 74.08) . 100 = 43.2 %

(2 / 74.08) . 100 = 2.7%

im a smart one

7 0
2 years ago
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