Answer:
6.2 calories
Explanation:
Data Given:
change in temperature = 20 °C
specific heat of gold = 0.031 calories/gram °C
mass of gold = 10.0 grams
Amount of Heat = ?
Solution:
Formula used
Q = Cs.m.ΔT
Where:
Q = amount of heat
Cs = specific heat of gold = 0.031 calories/gram °C
m = mass
ΔT = Change in temperature
Put values in above equation
Q = 0.031 calories/gram °C x 10.0 g x 20 °C
Q = 6.2 calories
So option A is correct = 6.2 calories
So first you work out the ratio. The formula tells us that for every one 'amount' of Ca and Cthere will be 3x the amount of oxygen. So, the ratio is 1:1:3, (=5) therefore 70g divided by 5 = 14.
If 70g of CaCO3 is heated there will be (1x14) 14g Ca, (1x14) 14g C and (3x14) 42g of O.
Weight of CaO= 42+14, 56g
(I hope this is right! Good luck xx)
<span>One theory that explains why scientific theories grow stronger over time is because more scientists study and work on the theory. Over time as the theory is studied in greater depth it becomes more accepted.</span>