The acceleration of the rocket will be "56.2 m/s²".
According to the question,
The initial speed during launch,
The speed at fuel running out point,
= 375 m/s
Height,
= 1250 m
As we know,
→ 
or,
→ 
By putting the values, we get
→ 
→ 
→ 
Thus the above solution is correct.
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Answer:
1962 W
Explanation:
P = W/t
P = F d cos theta / t
P = (500 kg) (9.81 m/s^2) (10 m) (cos 180) / 25 s <-- the displacement and the force act in opposite directions (but it doesn't matter because direction doesn't matter in this case)
P = 1962 W
Answer:
the answer is D
Explanation:
if you read the paragraph and question number 4 it tells you the answer wich is d
Answer:
16
Explanation:
solution:
by taking the ratio of the energy E_n,be of the nth orbit of a beryllium atom
Z_be=4 to the energy E_n,h of the nth orbit of a hydrogen (Z_h=1) atom gives
E_n,B/E_n,H=-(2.18*10^-18)*Z^2_BE/-(2.18*10^-18)*Zh^2/n^2
=Z^2_BE+/Z^2_H
=(4)^2/(1)^2
= 16
