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2 years ago

12

What is the height of a building that an object is dropped from if it has a mass of 3 kg and hits the ground with a velocity of

50 m/s?

1 answer:

Marizza181 [45]2 years ago

8 0

Answer:

125 m

Explanation:

m = 3kg

v = 50m/s

u = 0m/s

a = +g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

50² = 0² + 2(10)(H)

2500 = 20H

H = 2500/20

H = 125m

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Thepotemich [5.8K]

Answer:

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Explanation:

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3 years ago

What is the magnitude of the change in potential energy of the block-spring system when it travels from its lowest vertical posi

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Answer:

ΔU = 2 mg h

Explanation:

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instead in this energy it is

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3 years ago

Write a difference between force and work?

Nesterboy [21]

Answer:

force is a derived quantity

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Explanation:

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3 years ago

Read 2 more answers

A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec

olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

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stealth61 [152]

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2 years ago