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marissa [1.9K]
3 years ago
12

What is step one of a star called?​

Physics
1 answer:
yKpoI14uk [10]3 years ago
3 0

Answer: Stage 1- Stars are born in a region of high density Nebula, and condenses into a huge globule of gas and dust and contracts under its own gravity. This image shows the Orion Nebula or M42 . Stage 2 - A region of condensing matter will begin to heat up and start to glow forming Protostars.

Explanation:

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What’s the net force of an object being throwing into the air
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Answer: forces acting on an object being thrown into the air is gravity and possibly air resistance

Explanation:

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Si el periodo de oscilación de resorte es de 0,44 segundos cuando oscila atado a una masa de 2 Kg. ¿Cuál será el valor de la con
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A gold nucleus is 466 fm (1 fm = 10-15 m) from a proton, which initially is at rest. When the proton is released, it speeds away
Artist 52 [7]

Answer:

v=6.8\times10^6m/s

Explanation:

The sum of the kinetic and electric potential energies of the proton when initially released must be equal to their sum at infinity, so we have:

K_i+U_i=K_f+U_f

Which, since K_i=0J because initially the proton is at rest, is:

\frac{kqQ}{d}=\frac{mv^2}{2}+\frac{kqQ}{r_\infty}

where k=9\times10^9Nm^2/C^2 is Coulomb's constant, q=1.6\times10^{-19}C the charge of the proton, Q=(79)(1.6\times10^{-19})C the charge of the gold nucleus, since it has 79 protons, d=466\times10^{-15}m the initial separation between them, m=1.67\times10^{-27}kg the mass of the proton and v its final velocity. r_\infty is very far away, so the final electric potential will be 0J, and we have:

v=\sqrt{\frac{2kqQ}{md}}=\sqrt{\frac{2(9\times10^9)(1.6\times10^{-19})^2(79)}{(1.67\times10^{-27})(466\times10^{-15})}}m/s=6839409m/s

8 0
3 years ago
Which of the following are NOT examples of digital information storage?
VikaD [51]
Vinyl records because it’s not a secure information storage
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3 years ago
Read 2 more answers
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Snezhnost [94]

Answer:

I think 1.022 or 1

Explanation:

6 0
2 years ago
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