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musickatia [10]
4 years ago
6

A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he

at of the block?

Physics
1 answer:
igor_vitrenko [27]4 years ago
5 0

Answer:

508 J/kg/C

Explanation:

Energy Lost by water = Energy gained by block

mcT = <em>m</em><em>c</em><em>T</em><em> </em><em> </em>[bolded is for water, <em>i</em><em>t</em><em>a</em><em>l</em><em>i</em><em>c</em><em>i</em><em>s</em><em>e</em><em>d</em><em> </em>is for block]

(0.217)(4186)(25 - 16.4) = <em>(</em><em>0</em><em>.</em><em>3</em><em>5</em><em>0</em><em>)</em><em>(</em><em>c</em><em>)</em><em>(</em><em>1</em><em>6</em><em>.</em><em>4</em><em> </em><em>+</em><em> </em><em>2</em><em>7</em><em>.</em><em>5</em><em>)</em>

<em>1</em><em>5</em><em>.</em><em>3</em><em>6</em><em>5</em><em>c</em><em> </em>= 7811.9132

c = <u>5</u><u>0</u><u>8</u><u> </u><u>J</u><u>/</u><u>k</u><u>g</u><u>/</u><u>C</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u>

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The top of a swimming pool is at ground level. If the pool is 3.00 m deep, how far below ground level does the bottom of the poo
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Answer:

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b) 2.625 m

Explanation:

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In terms of real and apparent depth, the refractive index is given by

η = (real depth)/(apparent depth)

a) Real depth = 3.00 m

Apparent depth = ?

Refractive index, η = 1.333

1.333 = 3/(apparent depth)

Apparent depth = 3/1.3333 = 2.25 m.

Hence the bottom of the pool appears to be 2.25 m below the ground level.

b) Real depth = 1.5 m

Apparent depth = ?

Refractive index, η = 1.333

1.3333 = 1.5/(apparent depth)

Apparent depth = 1.5/1.3333 = 1.125 m

But the pool is half filled with water, there is a 1.5 m depth on top of the pool before refraction starts.

So, apparent depth of the pool = 1.5 + 1.125 = 2.625 m below the ground level

4 0
3 years ago
State the basic assumptions of the kinetic theory.
My name is Ann [436]

Answer:

option a

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6 0
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Inside a vacuum tube, an electron is in the presence of a uniform electric field with a magnitude of 320 N/C. (a) What is the ma
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<h3>Acceleration of the electron</h3>

The acceleration of the electron is calculated as follows;

F = qE

ma = qE

a = qE/m

a = (1.6 x 10⁻¹⁹ x 320)/(9.11 x 10⁻³¹)

a = 5.62 x 10¹³ m/s²

<h3>Speed of the electron</h3>

v = at

v = 5.62 x 10¹³ m/s² x  8.50 x 10⁻⁹ s

v = 4.78 x 10⁵ m/s

Learn more about speed here: brainly.com/question/4931057

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7 0
2 years ago
URGENT
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Answer:

give \\ mass(m) = 1350kg  \\ acceleration(a) = 1ms {}^{ - 2}  \ \\ sln\ \\  from \: our \: formula \\  \: f = ma \\1350kg \times 1ms {}^{ - 2}  \\ f = 1350newton

the force you applied to your car =1350N

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