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3 years ago

9

a track coach with a meter stick and a stopwatch is trying to determine if a student is walking with constant speed.he should...

1 answer:

Aleksandr [31]3 years ago

7 0

Give you a device that tracks your speed?

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The dimension line is connected to the part being measured by _______________. A. Hidden lines B. Extension lines C. Visible lin

kondaur [170]

B: Extension Lines! You could have just searched this up on google

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3 years ago

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How is temperature related to the physical change of a<br>substance

blagie [28]

Answer:

~~Now, you have left your question very open ended and didn't ask for any particular kind of answer so I'll do my best to get what you're looking for.~~

A physical change in a substance doesn't change what the substance is. It can possibly melt or freeze an object. I mean heat makes things expand while cooling makes them retract.... In chemical change where there is a chemical reaction, a new substance is formed and energy is either given off or absorbed.

4 0

3 years ago

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In a building with 10.000 cubic feet where the air changes every two hours, what the rate of air change? A. 167.7 cfm B. 83.3 cf

Naya [18.7K]

Answer:

Flow rate of air is given as 83.33 cubic feet per minute

Explanation:

As we know that total volume of the air flow is given as

$V = 10,000 cubic feet$

also we know that total time is

$t = 2 hours = 120 min$

now we have flow rate given as

$Q = \frac{V}{t}$

$Q = \frac{10000}{120}$

$Q = 83.3 cf/m$

3 0

3 years ago

How much time will it take a car travelling at 88 km/hr (55 mi/hr) to travel 500km

Elis [28]

<span>500 km x (1 hr/88 km) = 5.68 hrs</span>

4 0

3 years ago

A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso

jasenka [17]

Answer:

$U(3)=-43J$

Explanation:

Potential energy is minus the integral of Fdx. Doing the integration yields:

$U=\int\limits {6.0x+12}\, dx$

$U=-3x^2-12x+C$

$U(0)=20J$

so

$U(0)=-3(0)^2+12(0)+C=20$

$C=20$

Now for x=3.0m

$U(3)=-3*(3)^2-12(3)+20$

$U(3)=-43J$

6 0

3 years ago