K = 39 g/mol
KNO3 = 101 g/mol
2 KNO3 + 10 K = 6 K2O + N2
2 x 101 g KNO3 ---------- 10 x 39 g K
122 g KNO3 -------------- ??
122 x 10 x 39 / 2 x 101 =
47580 / 202 => 235.54 g of K
( KNO3 is Excess reagent )
2 x 101 g KNO3 ---------- 10 x 39 g K
?? --------------------------- 155 g K
155 x 2 x 101 / 10 x 39 =
31310 / 390 => 80.28 g of KNO3 ( K is <span>limiting reagent )
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hope this helps!
To get the atomic mass you need to combine the neutrons and protons together, and the atomic number is the number of protons in an atom!
Hope this helps if not comment below please!!!
Answer:
The glassware and solvent for the production of grignard reagent and its reaction should by dry and anhydrous so as to prevent the conversion of the grignard reagent into saturated alkane. Acetone, is not a good solvent for the generation of grignard reagent because it has the potential of forming alcohol.
Explanation:
Grignard reagent is a compound formed by the reaction of halide of alkyl or alkene with magnesium metal. This makes the compound more nucleophilic. Thus the availability of an electrophile around it will evoke a quick reaction. The presence of water in an acidic condition will generate hydroxonium ions which are highly electrophilic. There will therefore be an introduction of hydrogen ions to the grignard reagent and which will displace the MgBr leading to the formation of alkane.
Acetone tends to produce alcohol when they are exposed to grignard reagent, thus they are not appropriate to be used as solvent. This is due to the resultant highly electrophilic nature of the carbonyl carbon on the acetone, thus will react with the nucleophilic carbon on the grignard. The reaction can be represented as follows:
RMgBr + CH3(CO)CH3 + H (with hydrogen ions) >>>RCOH + Mg(OH)Br
Idk 0? I thought when an object is at potential energy it at its lowest point. Sorry guess this doesn't help If I just had the lesson I may be able 2 help.
Answer:
there is a little something called poop.
Explanation:
about that rasputia.
