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galben [10]
2 years ago
13

A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (ve

rtical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.

Physics
1 answer:
Lemur [1.5K]2 years ago
5 0

The Force on the left hand pole, F' = 0.167N

<h3>What is the force on the left hand pole?</h3>

Force is an agent which produces a change in the motion or state of an object.

Force is a vector quantity.

The general force is calculated as follows:

F = mg/sinθ

m = 17.1 g = 0.0171 kg

g = 9.81 m/s²

θ = 45°

F = 0.0171 * 9.81/sin45

F = 0.237 N

Force on the left hand pole, F' = Fcosθ

F' = 0.237 * cos 45

F' = 0.167N

In conclusion, the force on the left hand pole is the horizontal component of force.

Learn more about force at: brainly.com/question/141439

#SPJ1

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Answer:

There are 45 turns in the secondary coil.

Explanation:

Given that,

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The output potential of the lamp, V_{out}=1.5\ V

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We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\

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3 years ago
1.
Shalnov [3]

Answer:

No.

Explanation:

Given the following :

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The highest point in the track could be considered as the diameter of the circle :

Radius = diameter / 2;

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0.5(5^2) = 9.8h

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12.5 = 9.8h

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7 0
4 years ago
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The answer is:

Fill in the blanks to complete the sentence.

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