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galben [10]
2 years ago
13

A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (ve

rtical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.

Physics
1 answer:
Lemur [1.5K]2 years ago
5 0

The Force on the left hand pole, F' = 0.167N

<h3>What is the force on the left hand pole?</h3>

Force is an agent which produces a change in the motion or state of an object.

Force is a vector quantity.

The general force is calculated as follows:

F = mg/sinθ

m = 17.1 g = 0.0171 kg

g = 9.81 m/s²

θ = 45°

F = 0.0171 * 9.81/sin45

F = 0.237 N

Force on the left hand pole, F' = Fcosθ

F' = 0.237 * cos 45

F' = 0.167N

In conclusion, the force on the left hand pole is the horizontal component of force.

Learn more about force at: brainly.com/question/141439

#SPJ1

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According to Newton's third law of motion, which are equal
dem82 [27]

As per Newton's III law

Every action force that is applied on an object must be equal and opposite to reaction force applied by that object.

It can be said that when we apply any force on an object then this applied force is known as action force and at the same time that object also apply an opposite direction force on us which is known as reaction force having same magnitude.

So as per above theory

Action Force = Reaction Force (magnitude)

while both forces are always opposite in direction

7 0
3 years ago
I NEED HELP PLEASE, THANKS! Light passes from air into water at an angle of 40.0° to the normal. What is the angle of refraction
Vlad [161]

Answer:

Angle of Refraction = 28.9 degrees

Explanation:

<u><em>We'll use Snell's law for this. It's mathematical form is:</em></u>

=> n_1* sin(\alpha _1)=n_2 * sin(\alpha _2)

Where n_{1} = 1, n_{2} = 1.33, \alpha _{2} = 40^o

=> n_{1} and n_{2} are the refractive indexes of the air and water respectively.

<u><em>Solution:</em></u>

=> 1 * sin (40) = 1.33 * sin(\alpha _{2})

=> sin \alpha _{2} = \frac{sin 40^0}{1.33}

=> sin \alpha _{2} = 0.4821

=> \alpha _{2} = 28.9 degrees

8 0
3 years ago
At what speed would a 3.00 x 10^4 kg airplane have to fly and with a momentum of 1.60 x 10^9 kg.m/s
Ymorist [56]

Answer:

5.3×10⁴ m/s

Explanation:

From the question,

Momentum = mass× velocity

M = mV................ Equation 1

Where M = momentum of the airplane, m = mass of the airplane, V = Velocity of the airplane

make V the subject of the equation

V = M/m.................. Equation 2

Given: M = 1.6×10⁹ Kg.m/s, m = 3.0×10⁴ kg

Substitute these values into equation 2

V = 1.6×10⁹/3.0×10⁴

V = 5.3×10⁴ m/s

3 0
3 years ago
The research of social psychologist Vincent Hsu determined that Americans tend to fulfill their ideal of self-reliance through
dsp73
I think the correct answer from the choices listed above is option C. The research of social psychologist vincent hsu determined that americans tend to fulfill their ideal of self-reliance through <span> developing personal ideals. Hope this answers the question.</span>
3 0
3 years ago
A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 6.0 oz. Aluminum has a density of 2.70 g/cm3. Wh
SIZIF [17.4K]

Answer:

1.36 x 10^-3 cm

Explanation:

Area = 50 ft^2 = 46451.5 cm^2

mass = 6 oz = 170.097 g

density = 2.70 g/cm^3

Let t be the thickness of foil in cm.

mass = volume x density

mass = area x thickness x density

170.097 = 46451.5 x t x 2.70

t = 1.36 x 10^-3 cm

Thus, the thickness of aluminium foil is 1.36 x 10^-3 cm.

3 0
3 years ago
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