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Brut [27]
3 years ago
7

True or False further the sun, the longer the shadow

Physics
2 answers:
xz_007 [3.2K]3 years ago
6 0

Answer: Yes the further the sun is away the longer the shadow is. At noon,the shadow is the shortest because its straight up above you. If this helps pls mark brainliest!

SpyIntel [72]3 years ago
6 0

Answer:

Further the sun, the longer the shadow; true.

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Question 7 of 25
tiny-mole [99]

Answer:

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

2Na + MgCl₂ → 2NaCl + Mg

Explanation:

A balanced chemical equation is a chemical equation that have an equal number of elements of each type on both sides of the equation

Among the given chemical reactions, we have;

2PBr₃ + 3Cl₂ → 2PCl₃ + 3Br₂

In the above reaction;

The number of phosphorus, P, on either side of the equation = 2

The number of bromine atoms, Br, on either side of the equation = 6

The number of chlorine atoms, Cl, on either side of the equation = 6

Therefore, the number of elements in the reactant side and products side of the reaction are equal and the reaction is balanced

The second balanced chemical reaction is 2Na + MgCl₂ → 2NaCl + Mg

In the above reaction, there are two sodium atoms, Na,  one magnesium atom and two chlorine atoms on both sides of the reaction, therefore, the reaction is balanced

6 0
2 years ago
Tartaric acid is present in spinach true or false ​
sertanlavr [38]

Answer:

<h2>false</h2>

Explanation:

because Oxalic acid is present in spinach

<h2>MARK ME AS BRAINLIST</h2>
7 0
3 years ago
The highest free-standing tower in North America is the CN Tower in Toronto, Canada. From a distance of 1km from its base, the a
Whitepunk [10]
The height of the tower and the distance from its base form a right angle triangle. Thus,
tan(∅) = height / base
tan(28.81) = height / 1,000 m
height = 549.98 meters
4 0
3 years ago
The radius of a conducting wire is doubled .What will be the ratio of its new specific resistance to the old one?
sladkih [1.3K]
The equation for the resistance R is: R=ρ*(l/A), where, ρ is electrical resistivity, l is the length of the conductor, and A is the surface area.

The initial surface area is:

A=r²π, then when we double the radius we get:
 
A₁=(2*r)²π=4*r²π=4*A

Initial resistance is: R=ρ*(l/A).

When we double the radius, resistance is: R₁=ρ*{ l / (4*A) }

The ratio of the new resistance to the old one:

R₁/R=[ρ*(l/A)] / [ ρ* { l / (4*A) } ] = ρ, l and A cancel out and we get:

R₁/R=(1/1)/(1/4)=4/1 
7 0
3 years ago
I NEEDHELP ASAP !!! BEIN TIMED AND I HAVE 5 MINS LEFT AND 8 LEFT TO ANSWER !
inn [45]

i think its a, good luck on your test

3 0
3 years ago
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