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Arte-miy333 [17]
3 years ago
6

If 1.38×1022 atoms of element y have a mass of 1.50 g, what is the identity of y? express your answer as a chemical symbol.

Chemistry
2 answers:
kifflom [539]3 years ago
7 0

Answer:1,38×10²² = 0,138×10²³

Explanation:

zaharov [31]3 years ago
4 0
1,38×10²² = 0,138×10²³

0,138×10²³ ----- 1,5g
6,02×10²³ ------ X
X = (1.5×6,02×10²³)/0,138×10²³
X = 65,435 g/mol

It's ZINC (Zn)

:•)
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Explanation:

<u>Given:</u>

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<u>To determine:</u>

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<u>Calculation:</u>

Set-up an ICE table for the given reaction:

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E               x                  (0.0546-x)    (0.0546-x)

Kc = \frac{[SbCl3][Cl2]}{[SbCl5]}\\\\1.7*10^{-3} =\frac{(0.0546-x)^{2} }{x} \\\\x = 0.0457 M

The equilibrium concentration of Cl2 is:

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