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viva [34]
3 years ago
7

How do i write a report about Gold mining?

Chemistry
1 answer:
pentagon [3]3 years ago
4 0
<u><em>Your Essay Must include:</em></u>
<u><em>Introduction:Brings the main idea,Must be atleast 3 sentences.</em></u>
<u><em>Body/Details:Supports the main Idea,Must be atleast 8 sentences.</em></u>
<u><em>Body/Details(Optional):Supports the main Idea,Must be atleast 8 sentences.</em></u>
<u><em>Conclusion:Tells a little more information.</em></u>


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I need help understanding this problem and the answer.
victus00 [196]

Answer:-

1440 cases

Explanation: -

We are told that 1 pallet = 45 bundles.

We are also told that 1 bundle = 32 cases.

We need to find how many cases are there in 1 pallet.

1 pallet = 45 bundles (First conversion factor)

= 45 x 32 cases (second conversion factor)

=1440 cases

Thus we see that 1 pallet has 1440 cases. We needed to use two conversion factors for this, first to convert pallet to bundle and second to convert bundle to cases.

5 0
3 years ago
Methanol, ethanol, and n−propanol are three common alcohols. When 1.00 g of each of these alcohols is burned in air, heat is lib
KengaRu [80]

Answer:

<u>For methanol:</u> Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)

<u>For ethanol: </u>Heat of combustion = -29.7 kJ / 0.0217 moles = -1368.6636 kJ/mol (negative sign signifies release of heat)

<u>For propanol: </u>Heat of combustion = -33.4 kJ / 0.0166 moles = -2012.0482 kJ/mol (negative sign signifies release of heat)

Explanation:

Given:

Mass of Methanol = 1.0 g

Mass of ethanol = 1.00 g

Mass of n-propanol = 1.00 g

<u>For methanol:</u>

2 CH₃OH + 3 O₂ ----> 2 CO₂ + 4 H₂O, ∆H₀ = -22.6 kJ/g  (negative sign signifies release of heat)

1 g of methanol on combustion gives 22.6 kJ of energy

Calculation of moles of methanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of methanol = 32.04 g/mol

Thus moles of methanol = 1 g/ (32.04 g/mol) = 0.0312 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -22.6 kJ / 0.0312 moles = -724.3590 kJ/mol (negative sign signifies release of heat)</u>

<u></u>

<u>For ethanol:</u>

C₂H₅OH + 3 O₂ ----> 2 CO₂ + 3 H₂O, ∆H₀ = -29.7 kJ/g  (negative sign signifies release of heat)

1 g of ethanol on combustion gives 29.7 kJ of energy

Calculation of moles of ethanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of ethanol = 46.07 g/mol

Thus moles of ethanol = 1 g/ (46.07 g/mol) = 0.0217 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -29.7 kJ / 0.0217 moles = -1368.6636 kJ/mol (negative sign signifies release of heat)</u>

<u></u>

<u>For propanol:</u>

2 C₃H₇OH + 9 O₂ ----> 6 CO₂ + 8 H₂O, ∆H₀ = -33.4 kJ/g , (negative sign signifies release of heat)

1 g of methanol on combustion gives 33.4 kJ of energy

Calculation of moles of methanol:

moles=\frac{Mass(m)}{Molar\ mass (M)}

Molar mass of methanol = 60.09 g/mol

Thus moles of methanol = 1 g/ (60.09 g/mol) = 0.0166 moles

Hence energy in kJ/mol:

<u>Heat of combustion = -33.4 kJ / 0.0166 moles = -2012.0482 kJ/mol (negative sign signifies release of heat)</u>

5 0
3 years ago
A substance stores ___________ as a result of its chemical bonds.
Maksim231197 [3]

Answer:

Chemical energy

3 0
3 years ago
Please help me, or just tell me what laws they are (Boyle's law, Charles
Vlada [557]

Answer:

Boyle's law states that the volume of a fixed mass of agass at constant temperature is inversely proportional to its pressure

6 0
2 years ago
As you move from top to bottom down a group on the periodic table the size of an atone will
marin [14]

Answer:

Get Bigger

Explanation:

6 0
4 years ago
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