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abruzzese [7]
2 years ago
10

The density of molybdenum is 10.28 g/cm^3 and it crystallizes in the face centered cubic unit cell. Calculate the edge length of

the unit cell. (The atomic mass of Mo is 95.96 g/mole)
Physics
1 answer:
Effectus [21]2 years ago
4 0

The edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

<h3>Volume of molybdenum</h3>

V = (zm/ρN)

where;

  • z is 2 for cubic unit cell
  • m is mass of the molybdenum
  • ρ is density of the molybdenum

V = (2 x 95.96) / (10.28 x 6.02 x 10²³)

V = 3.10 x 10⁻²³ cm³

<h3>Edge length of the unit cell</h3>

a³ = V

a = (V)^¹/₃

a = ( 3.10 x 10⁻²³)^¹/₃

a = 3.142 x 10⁻⁸ cm

a = 3.142 x 10⁻¹⁰ m

a = 314.2 x 10⁻¹² m

a = 314.2 pm

Thus, the edge length of the unit cell at the given atomic mass and density of the molybdenum is 314.2 pm.

Learn more about edge length here:

brainly.com/question/16673486

#SPJ1

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An early submersible craft for deep-sea exploration was raised and lowered by a cable from a ship. When the craft was stationary
Assoli18 [71]

Answer:

The tension in the cable when the craft was being lowered to the seafloor is 4700 N.

Explanation:

Given that,

When the craft was stationary, the tension in the cable was 6500 N.

When the craft was lowered or raised at a steady rate, the motion through the water added an 1800 N.

The drag force of 1800 N will act in the upward direction. As it was lowered or raised at a steady rate, so its acceleration is 0. As a result, net force is 0. So,

T + F = W

Here, T is tension

F = 1800 N

W = 6500 N

Tension becomes :

T=W-F\\\\T=6500-1800\\\\T=4700\ N

So, the tension in the cable when the craft was being lowered to the seafloor is 4700 N.

7 0
3 years ago
Consider two transformers. Transformer A has 300 turns on its primary and 500 turns on its secondary. Transformer B has 250 turn
rusak2 [61]

Answer:

Secondary voltage on second transformer is 200 volt.

Explanation:

It is given two transformer

Let us consider first transformer.

Number of turns in primary N_p=300

Numb er of turns in secondary N_s=500

Now consider second transformer

Number of turns in primary N_p=250

Number of turns in secondary N_s=1000

Now it is given that same voltage of 50 volt is applied to primary of both the transformer.

For second transformer

\frac{N_p}{N_s}=\frac{V_p}{V_s}

\frac{250}{1000}=\frac{50}{V_s}

V_s=200volt

So secondary voltage on second transformer is 200 volt

4 0
4 years ago
PLZ HELP DUE IN 10MIN!!!!!!!!!The temperature of the water vapor (H2O) inside a pressure cooker increased from 295 K to 395 K. A
madreJ [45]

Did you ever figure it out, bc now I need it lol.

3 0
3 years ago
When friction occurs, which of the following types of energy is produced?
sukhopar [10]

Answer:

heat energy

Explanation:

Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer.

8 0
2 years ago
Read 2 more answers
If we wish to expand (x + y) 8 , what is the coefficient of x 5 y 3 ? what is the coefficient of x 3 y 5 ?
Molodets [167]
We use the binomial theorem to answer this question. Suppose we have a trinomial (a + b)ⁿ, we can determine any term to be:

[n!/(n-r)!r!] a^(r) b^(n-r)

a.) For x⁵y³, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.

r = 5
n - r = 3
Solving for n,
n = 3 + 5 = 8

Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-5)!8! = 56

b.) For x³y⁵, the variables are: x=a and y=b. We already know the exponents of the variables. So, we equate this with the form of the binomial theorem.

r = 3
n - r = 5
Solving for n,
n = 5 + 3 = 8

Therefore, the coefficient is equal to:
Coefficient = n!/(n-r)!r! = 8!/(8-3)!8! = 56
7 0
3 years ago
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