Answer:
Ya inan bana çok özür dilerim cevabı bilmiyorum ama ilk defa bugün indirdim ve hiç türk yoktu selam vermek istedim selam jwlwpskwks herkes yabancı burda neden?
Answer:
Acceleration a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2
Explanation:
For the truck to accelerate without losing its load.
Acceleration force of truck must be less than or equal to the maximum friction force between the truck bed and the load.
Fa ≤ F(friction)
But;
Fa = mass × acceleration
Fa = ma
ma ≤ F(friction)
a ≤ (F(friction))/m ......1
Given;
Fa = mass × acceleration
Fa = ma
mass m = 800 kg
F(friction) = 2400 N
Substituting the given values into equation 1;
a ≤ F(friction)/m
a ≤ 2400N/800kg
a ≤ 3 m/s^2
the greatest acceleration that the truck can have without losing its load is 3 m/s^2
Answer:
r = 5,085 m
Explanation:
The force exerted by on the surface of the Earth on an electron is its weight
W = F = 9.11 10⁻³¹ 9.8
W = 8.9 10⁻³⁰ N
The electric force between an electron and a proton is given by Coulomb's Law
Fe = k q₁ q₂ / r²
Fe = - k q² / r²
They ask us that W = Fe
W = k q² / r²
r = √ k q² / W
Let's calculate
r = √ 8.99 10⁹ (1.6 10⁻¹⁹)² /8.9 10⁻³⁰
r = √ 25.86
r = 5,085 m
Let's look for the relationship of this distance with the harmonic distance
R / R_atomic = 5,085 / 10⁻¹⁰
R / R_Atomic = 5 10¹⁰
We see that this distance is 10¹⁰ times the interatomic distance, so the gravitational attraction force is very small at atomic scale
