<h3>
Answer:</h3>
KE = 1000 J
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Physics</u>
<u>Energy</u>
Kinetic Energy Formula: ![\displaystyle KE = \frac{1}{2}mv^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20KE%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2)
- Energy is in Joules
- m is mass (in kg)
- v is velocity (in m/s)
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
m = 20 kg
v = 10 m/s
<u>Step 2: Find KE</u>
- Substitute [KE]:
![\displaystyle KE = \frac{1}{2}(20)(10)^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2820%29%2810%29%5E2)
- Exponents:
![\displaystyle KE = \frac{1}{2}(20)(100)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20KE%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2820%29%28100%29)
- Multiply:
![\displaystyle KE = (10)(100)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20KE%20%3D%20%2810%29%28100%29)
- Multiply:
![\displaystyle KE = 1000](https://tex.z-dn.net/?f=%5Cdisplaystyle%20KE%20%3D%201000)
Answer:
I think the Answer is B. Longitudinal waves
V = final velocity
u = initial velocity
a = acceleration
s = displacement
Take downward direction as positive.
v^2 = u^2 + 2as
v^2 = 0.8^2 + 2(1.6)(5.5)
v^2 = 18.24
v = 4.27 m/s
Answer:
option C
Explanation:
Given,
Refractive index of medium 1 = n₁
Refractive index of medium 2 = n₂
For total internal reflection to take place light should move from denser medium to the rarer medium.
Here Total internal reflection take place at the boundary of medium 1 and medium 2 so, the refractive index of medium 1 is more than medium 2
n₁ > n₂
The correct answer is option C