1 answer:
The current density of the copper wire is determined as (7.059 x 10⁸ A/m²)/L
<h3>Current density of the copper wire</h3>
The current density of the copper wire is calculated as follows;
J =1/ρ(E) = 1/ρ(V/L)
where;
- E is electric field
- V is voltage
- L is length of the wire
<h3>Current density the wire</h3>
J =1/ρ(E) = 1/ρ(V/L)
J = (1/1.7 x 10⁻⁸) x (12)/L
J = (7.059 x 10⁸ A/m²)/L
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