Question

The resistivity of

Answer 1

The current density of the copper wire is determined as (7.059 x 10⁸ A/m²)/L

Current density of the copper wire

The current density of the copper wire is calculated as follows;

J =1/ρ(E) = 1/ρ(V/L)

where;

• E is electric field
• V is voltage
• L is length of the wire

Current density the wire

J =1/ρ(E) = 1/ρ(V/L)

J = (1/1.7 x 10⁻⁸) x (12)/L

J = (7.059 x 10⁸ A/m²)/L

Learn more about current here: brainly.com/question/24858512

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