a runner runs 2.88 m/s north. she accelerates .350 m/s ^2 at a -52.0 degree angle at the point in the motion where she is runnin
1 answer:
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Answer:
<em>An average net force of 5200 N is needed to stop the car</em>
Explanation:
<u>Cinematics and Dynamics</u>
Cinematics describes the variables involved in the movement without dealing with its causes. There are four main concepts in cinematics: Velocity (or its scalar equivalent, the speed), acceleration, time, and displacement (or the scalar equivalent, distance).
The acceleration can be calculated by:
The initial speed is vo=28 m/s, it stops (vf=0) in t=10.5 seconds, thus the acceleration is:
The acceleration is negative because the car loses speed.
Knowing the mass of the car m=1950 Kg, we can calculate the net force required to stop the car by using the formula:
F = m.a =1950*2.67
F = 5200 N
An average net force of 5200 N is needed to stop the car
Answer:
It would be a straight line
Explanation:
On a distance-time graph, an object that moves at constant speed would be represented by a straight line.
In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:
- The speed of the object is equal to the ratio between the distance covered and the time taken (
):
On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:
But the variation on the y-axis () is equal to the distance covered (
), while the variation on the x-axis
corresponds to the time taken (
), so the slope can also be rewritten as
which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.