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2 years ago

A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?

Physics

2 answers:

S_A_V [24]2 years ago

7 0

Answer:

Force, F = 57.134 N

Explanation:

It is given that,

Mass of the sled, m = 53 kg

Coefficient of kinetic friction, $\mu_k=0.11$

We need to find the force of friction felt by sled. The force of friction is given by :

$F=\mu mg$

$F=0.11\times 53\ kg\times 9.8\ m/s^2$

F = 57.134 N

So, the force of friction felt by the sled is 57.134 N. Hence, this is the required solution.

Anon25 [30]2 years ago

6 0

Answer:

57N

Explanation:

$F_F = \mu F_N = \mu mg = 0.11 \times 53 kg \times 9,8 \frac{m}{s^{2} }$

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Explanation:

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1 year ago

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

mel-nik [20]

Answer:

Explanation:

All the displacement will be converted into vector, considering east as x axis and north as y axis.

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D = 5.3 j

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D₁= 8.3 cos 50 i + 8.3 sin 50 j.

= 5.33 i + 6.36 j

Let D₂ be the displacement which when added to D₁ gives the required displacement D

D₁ + D₂ = D

5.33 i + 6.36 j + D₂ = 5.3 j

D₂ = 5.3 j - 5.33i - 6.36j

= - 5.33i - 1.06 j

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D₂²= 5.33² + 1.06²

D₂ = 5.43 km

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3 years ago

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Answer:

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2 years ago

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3 years ago

Read 2 more answers