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MA_775_DIABLO [31]
3 years ago
12

A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?

Physics
2 answers:
S_A_V [24]3 years ago
7 0

Answer:

Force, F = 57.134 N  

Explanation:

It is given that,

Mass of the sled, m = 53 kg

Coefficient of kinetic friction, \mu_k=0.11

We need to find the force of friction felt by sled. The force of friction is given by :

F=\mu mg

F=0.11\times 53\ kg\times 9.8\ m/s^2

F = 57.134 N

So, the force of friction felt by the sled is 57.134 N. Hence, this is the required solution.

Anon25 [30]3 years ago
6 0

Answer:

57N

Explanation:

F_F = \mu F_N = \mu mg = 0.11 \times 53 kg \times 9,8 \frac{m}{s^{2} }

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crimeas [40]
If you mean S is the distance then it is true 
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3 0
3 years ago
What material parameters determine resistivity?
sleet_krkn [62]

Answer:

Resistivity \rho =\frac{RA}{l}

It depends upon cross sectional area and length of material

Explanation:

The resistance of any material is given by R=\frac{\rho l}{A}, here \rho is the resistivity of material , l is length of material and A is cross sectional area

So resistivity \rho =\frac{RA}{l}

So resistuivity of any material depends upon area of cross section and length of material

If cross sectional area will be more then resistivity will be more. And is length of the material will be more then resistivity will be less

3 0
3 years ago
Consider two waves defined by the wave functions y1(x,t)=0.50msin(2π3.00mx+2π4.00st) and y2(x,t)=0.50msin(2π6.00mx−2π4.00st). Wh
guapka [62]

Answer:

They two waves has the same amplitude and frequency but different wavelengths.

Explanation: comparing the wave equation above with the general wave equation

y(x,t) = Asin(2Πft + 2Πx/¶)

Let ¶ be the wavelength

A is the amplitude

f is the frequency

t is the time

They two waves has the same amplitude and frequency but different wavelengths.

4 0
3 years ago
A weightlifter curls a 30 kg bar, raising it each time a distance of 0.60 m. How many times must he repeat this exercise to burn
Sholpan [36]

Answe

given,

mass of the bar, m = 30 Kg

distance of rise, h = 0.60 m

Assuming the efficiency = 25 %

energy from the pizza slice = 300 C = 1260 kJ

To consume Energy from the pizza bar is to be pulled several number of time.

( energy from pizza ) x (efficiency) = n m g h

n is the number of lift

( 1260 x 10³) x (0.25) = n x 30 x 9.8 x 0.6

n = \dfrac{315\times 10^3}{176.4}

     n = 1786 times.

Weightlifter should lift bar 1786 times to burn off the energy.

8 0
3 years ago
A major artery with a 1.6 cm2 cross-sectional area branches into 18 smaller arteries, each with an average cross-sectional area
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To solve this problem it is necessary to apply the continuity equations for which it is defined that the proportion of Area in the initial section is equal to the final section. In other words,

A_1 v_1 = A_2 v_2

Where,

A_i = Cross sectional area at each section

v_i =Velocities of fluid at each section

The total area of the branch is eighteen times of area of smaller artery. The average cross-sectional area of each artery is 0.7cm^2.

Therefore the Cross-sectional area at the end is

A_2= 18*0.7cm^2

A_2 = 12.6cm^2

Applying the previous equation we have then

A_1 v_1 = A_2 v_2

(1.7cm^2) v_1 = (12.6cm^2)v_2

The ratio of the velocities then is

\frac{v_1}{v_2} = \frac{1.7}{12.6}

\frac{v_1}{v_2} = 0.135

Therefore the factor by which the velocity of blood will reduce when it enters the smaller arteries is 0.1349

5 0
4 years ago
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