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MA_775_DIABLO [31]
2 years ago
12

A 53.0 kg sled is sliding on snow with μk=0.110. how much friction force does it feel?

Physics
2 answers:
S_A_V [24]2 years ago
7 0

Answer:

Force, F = 57.134 N  

Explanation:

It is given that,

Mass of the sled, m = 53 kg

Coefficient of kinetic friction, \mu_k=0.11

We need to find the force of friction felt by sled. The force of friction is given by :

F=\mu mg

F=0.11\times 53\ kg\times 9.8\ m/s^2

F = 57.134 N

So, the force of friction felt by the sled is 57.134 N. Hence, this is the required solution.

Anon25 [30]2 years ago
6 0

Answer:

57N

Explanation:

F_F = \mu F_N = \mu mg = 0.11 \times 53 kg \times 9,8 \frac{m}{s^{2} }

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4 0
3 years ago
At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci
ozzi

Answer:

r=2.4m

Explanation:

We have to use the centripetal force  equation

Fc=\frac{mv^{2} }{r}

we  need the radious so we have to isolate "r" and we get

r=\frac{mv^{2} }{Fc}

replacing m=65 kg, v= 4.1 m/s and Fc=455N we get

r=\frac{65*4.1^{2} }{455}

r=2.4m

The radius of the amusement park chamber is 2.4m

4 0
2 years ago
An object is made up of three masses connected by massless rods of fixed length. Mass A is located at (30.0 cm, 0 cm) and has a
puteri [66]

Answer:

0.0605 Kg m^2

Explanation:

In this case where we have find he moment of inertia of this object about an axis perpendicular to the x-y plane and passing through the origin,  we can just add three moment of inertia's .

MOI= 0.25×0.3^2 + 0.35×0.4^2- 0.45×0.2^2

= 0.0605 Kg m^2

8 0
3 years ago
What are the four layers of the earth
kumpel [21]

Answer:

earth's crust

meatle

outercore

innercore

8 0
3 years ago
Read 2 more answers
Potrzebuję na teraz bardzo proszę
Andreyy89

Answer:

Niels bohr was the correct choise

Explanation:

bohr made the plum pudding model

5 0
2 years ago
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