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3 years ago

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What is the density of a block of aluminum that has mass 27 grams of and a volume 10 cm3? 2.7 g/cm3 270 g/cm3 0.37 g/cm3 0.37 cm

3/g

2 answers:

DENIUS [597]3 years ago

7 0

M=27 g
v=10 cm³

p=m/v

p=27/10=2.7 g/cm³

Akimi4 [234]3 years ago

6 0

Answer:

The answer is 2.7 g/cm³ :)

Explanation:

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vlada-n [284]

Answer:

El cocodrilo se arrastró durante 20.833 segundos.

Explanation:

El enunciado presenta omisiones y errores conceptuales. La forma correcta es la siguiente: <em>"Un cocodrilo se arrastró 25 metros hacia la derecha con una rapidez promedio de 1.2 metros por segundo. ¿Cuántos segundos se arrastró el cocodrilo?"</em>

Consideremos que el cocodrilo tiene un movimiento rectilíneo uniforme, el tiempo requerido para el recorrido se calcula con la siguiente ecuación cinemática:

$t = \frac{x}{v}$ (1)

Donde:

$x$ - Distancia recorrida, en metros.

$v$ - Rapidez del cocodrilo, en metros por segundo.

$t$ - Tiempo, en segundos.

Si $x = 25\,m$ y $v = 1.2\,\frac{m}{s}$ , entonces el tiempo empleado por el cocodrilo es:

$t = \frac{25\,m}{1.2\,\frac{m}{s} }$

$t = 20.833\,s$

El cocodrilo se arrastró durante 20.833 segundos.

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8 0

3 years ago

Draw the structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbo

Vlad1618 [11]

Answer:

Please see the attachments

Explanation:

Please see the attachments below structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbon.

3 0

3 years ago

Which of the following is equal to 3.3mm3? A) 3.3 x 10^-6 m^3 B) 3.3 x 10^-9 m^3 C) 3.3 x 10^-6 cm^3 D) 3.3 x 10^-9 cm^3

vazorg [7]

Step 1 - Since 3.3mm^3 = 0.0033cm^3, convert that to 3.3x10^-3 cm^3.

Step 2 - Since 1cm^3 = 1x10^-6 m^3, times 3.3 by that. (3.3 x 1 x 10^-6) = 0.0000033

Step 3 - 0.0000033 = 3.3 x 10 ^-6 m^3, which is your answer choice A.

*if you do not understand, message me and I will go through it more thoroughly!!*

Have a great day!! :)

3 0

3 years ago

Chlorine has two naturally occurring isotopes, 35C1 Gsotopic mass 34.9689 amu) and 370 (isotopic mass 36.9659 amu). If chlorine

Lilit [14]

<u>Answer:</u> The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 75.77% and 24.23% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

<u>For $_{17}^{35}\textrm{Cl}$ isotope:</u>

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 34.9689 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

<u>For $_{17}^{37}\textrm{Cl}$ isotope:</u>

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 36.9659 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.4527 amu

Putting values in equation 1, we get:

$35.4527=[(34.9689\times x)+(36.9659\times (1-x))]\\\\x=0.7577$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.7577\times 100=75.77\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.7577)=0.2423\times 100=24.23\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 75.77% and 24.23% respectively.

6 0

3 years ago

Which statement best describes the nuclear model of the atom. A) negative charges dispersed in a positively charged cloud B) pos

Svetradugi [14.3K]

Answer:

D.) small, dense negative nucleus surrounded by a diffuse positively charged cloud

Explanation:

I am not 100% sure but the reason I think this is the answer is because Protons and Neutrons are in the nucleus. Protons being positively charged and neutrons being negatively charged. Again, I do not know for sure, but I think D is the answer.

4 0

3 years ago