Answer:
8 × 10³ mol N₂
Explanation:
Step 1: Write the balanced equation
2 C₃H₅N₃O₉ ⇒ 6 CO₂ + 5 H₂O + 0.5 O₂ + 3 N₂
Step 2: Convert the mass of C₃H₅N₃O₉ from tons to grams
We will use the conversion factor 1 t = 907185 g.
1.320 t × 907185 g/1 t = 1.197 × 10⁶ g
Step 3: Calculate the moles corresponding to 1.197 × 10⁶ g of C₃H₅N₃O₉
The molar mass of C₃H₅N₃O₉ is 227 g/mol.
1.197 × 10⁶ g × 1 mol/227 g = 5.27 × 10³ mol
Step 4: Calculate the moles of N₂ formed from 5.27 × 10³ moles of C₃H₅N₃O₉
The molar ratio of C₃H₅N₃O₉ to N₂ is 2:3.
5.27 × 10³ mol C₃H₅N₃O₉ × 3 mol N₂/2 mol C₃H₅N₃O₉ = 7.91 × 10³ mol N₂ ≈ 8 × 10³ mol N₂
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Answer:
0.2 grams
Explanation:
The expression is already in decimal form! Hope this helps.
-Lei
answer
changing the temperature and increase in the pressure
Change in concentration, pressure, catalyst, inert gas addition, etc. have no effect on concentration, pressure, catalyst, inert gas addition lead to a shift in equilibrium position .