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nexus9112 [7]
3 years ago
9

What is the density of a block of aluminum that has mass 27 grams of and a volume 10 cm3? 2.7 g/cm3 270 g/cm3 0.37 g/cm3 0.37 cm

3/g
Chemistry
2 answers:
DENIUS [597]3 years ago
7 0
M=27 g
v=10 cm³

p=m/v

p=27/10=2.7 g/cm³
Akimi4 [234]3 years ago
6 0

Answer:

The answer is 2.7 g/cm³ :)

Explanation:

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Answer:

The wavelength for the transition from n = 4 to n = 2 is<u> 486nm</u> and the name  name given to the spectroscopic series belongs to <u>The Balmer series.</u>

Explanation

lets calculate -

Rydberg equation-   \frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})

where ,\pi is wavelength , R is Rydberg constant ( 1.097\times10^7), n_1 and n_2are the quantum numbers of the energy levels. (where n_1=2 , n_2=4)

Now putting the given values in the equation,

                \frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )=2056875m^-^1

    Wavelength \pi =\frac{1}{2056875}

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<u>    Therefore , the wavelength is 486nm and it belongs to The Balmer series.</u>

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