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yuradex [85]
3 years ago
5

What is the new temperature when 10 L at 5 K is compressed to 4.00 L

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer: C

Explanation:

For this problem, we would use Charles's Law. We fill in what we are given and solve.

Charles's Law: \frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

\frac{10 L}{5K} =\frac{4.00L}{T_{2} }

10T_{2}= 20

T_{2}=2K

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Answer: The pressure in atmospheres is 0.674 in the container if the temperature remains constant.

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = 205 kPa

P_2 = final pressure of gas = ?

V_1 = initial volume of gas  = 4.0 L

V_2 = final volume of gas = 12000 ml = 12 L    (1L=1000ml)  

205\times 4.0=P_2\times 12  

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Therefore, the pressure in atmospheres is 0.674 in the container if the temperature remains constant.

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3 years ago
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