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yuradex [85]
3 years ago
5

What is the new temperature when 10 L at 5 K is compressed to 4.00 L

Chemistry
1 answer:
lina2011 [118]3 years ago
4 0

Answer: C

Explanation:

For this problem, we would use Charles's Law. We fill in what we are given and solve.

Charles's Law: \frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

\frac{10 L}{5K} =\frac{4.00L}{T_{2} }

10T_{2}= 20

T_{2}=2K

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(b) <em>Thickness of foil </em>

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V  = lwh                            Divide each side by lw

h = V/(lw)

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   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.

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