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7nadin3 [17]
2 years ago
15

Balance each skeleton reaction, use Appendix D to calculate E°cell , and state whether the reaction is spontaneous:(a) Cu⁺(aq) +

PbO₂(s) + SO₄²⁻(a q) → PbSO₄(s) + Cu²⁺(aq) [acidic]
Chemistry
1 answer:
melamori03 [73]2 years ago
4 0

The balanced equation reaction :

2Cu+(aq) + PbO2(s) + SO42–(aq) + 4H+  -----------> PbSO4(s) + 2 Cu2+(aq)  + 2H2O

A balanced equation is an equation for a chemical reaction in which the range of atoms for every detail in the reaction and the full charge is identical for both the reactants and the products. In other phrases, the mass and the fee are balanced in each aspect of the reaction.

A balanced equation happens while the variety of the atoms involved inside the reactants side is identical to the variety of atoms in the goods facet. in this chemical reaction, nitrogen (N2) reacts with hydrogen (H) to provide ammonia (NH3). The reactants are nitrogen and hydrogen, and the product is ammonia.

A chemical equation is the symbolic representation of a chemical reaction inside the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities.

Eo  = Eored - Eo oxd

 = 1.69  - 0.153

 = 1.54 V

Eocell is positive so the reaction is spontaneous.

Learn more about the balanced reaction  here brainly.com/question/15355912

#SPJ4

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3 years ago
The partial pressure of N2 in the air is 593 mm Hg at 1 atm. What is the partial pressure of N2 in a bubble of air a scuba diver
Evgen [1.6K]

Answer: Partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

Explanation:

It is known that 1 atm = 760 mm Hg.

Also,   P_{N_{2}} = x_{N_{2}}P

where,    P_{N_{2}} = partial pressure of N_{2}

                 P = atmospheric pressure

            x_{N_{2}} = mole fraction of N_{2}

Putting the given values into the above formula as follows.

      P_{N_{2}} = x_{N_{2}}P

    593 mm Hg = x_{N_{2}} \times 760 mm Hg

       x_{N_{2}} = 0.780

Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of N_{2} is as follows.

         P_{N_{2}} = x_{N_{2}}P

                  = 0.78 \times 5 atm \times \frac{760 mm Hg}{1 atm}

                  = 2964 mm Hg

Therefore, we can conclude that partial pressure of N_{2} at a depth of 132 ft below sea level is 2964 mm Hg.

8 0
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