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7nadin3 [17]
2 years ago
15

Balance each skeleton reaction, use Appendix D to calculate E°cell , and state whether the reaction is spontaneous:(a) Cu⁺(aq) +

PbO₂(s) + SO₄²⁻(a q) → PbSO₄(s) + Cu²⁺(aq) [acidic]
Chemistry
1 answer:
melamori03 [73]2 years ago
4 0

The balanced equation reaction :

2Cu+(aq) + PbO2(s) + SO42–(aq) + 4H+  -----------> PbSO4(s) + 2 Cu2+(aq)  + 2H2O

A balanced equation is an equation for a chemical reaction in which the range of atoms for every detail in the reaction and the full charge is identical for both the reactants and the products. In other phrases, the mass and the fee are balanced in each aspect of the reaction.

A balanced equation happens while the variety of the atoms involved inside the reactants side is identical to the variety of atoms in the goods facet. in this chemical reaction, nitrogen (N2) reacts with hydrogen (H) to provide ammonia (NH3). The reactants are nitrogen and hydrogen, and the product is ammonia.

A chemical equation is the symbolic representation of a chemical reaction inside the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities.

Eo  = Eored - Eo oxd

 = 1.69  - 0.153

 = 1.54 V

Eocell is positive so the reaction is spontaneous.

Learn more about the balanced reaction  here brainly.com/question/15355912

#SPJ4

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When 69.9 g heptane is burned it releases __ mol water.
professor190 [17]

Answer:

1) When 69.9 g heptane is burned it releases 5.6 mol water.  

2) C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.

Explanation:

  • Firstly, we should balance the equation of heptane combustion.
  • The balanced equation is: <em>C₇H₁₆ + 11O₂ → 7CO₂ + 8H₂O.</em>

This means that every 1.0 mole of complete combustion of heptane will release 8 moles of H₂O.

  • We need to calculate the no. of moles in 69.9 g of heptane that is burned using the relation: <em>n = mass/molar mass.</em>

n of 69.9 g of heptane = mass/molar mass = (69.9 g)/(100.21 g/mol) = 0.697 mol ≅ 0.7 mol.

<em><u>Using cross multiplication:</u></em>

1.0 mol of heptane releases → 8 moles of water.

0.7 mol of heptane releases → ??? moles of water.

<em>∴ The no. of moles of water that will be released from burning (69.9 g) of water</em> = (0.7 mol)(8.0 mol)/(1.0 mol) = <em>5.6 mol.</em>

<em>∴ When 69.9 g heptane is burned it releases </em><em>5.6</em><em> mol water. </em>

<em />

5 0
3 years ago
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