Answer:
94.57 g H2O
Explanation:
32.0 g H2
Molar Mass H2: 2.01 g/mol
84.0 g O2
Molar Mass O2: 32.00 g/mol
Molar Mass H2O: 18.02 g/mol
First balance the eqution:
2H2 + O2 = 2H2O
Find the amount of moles that both 32.0 g of H2 and 84.0 g of O2 can produce using the molar masses:
32.0 g H2 x ((1 mole H2)/ (2.015 g H2)) = 15.88 moles H2
84.0 g O2 x ((1 mole O2)/(32.00 g O2)) = 2.63 moles O2
Now you can find the amount of grams of H2O each reactant will produce:
**keep in mind of mole ratios from balanced equation**
15.88 moles H2 x ((2 moles H2O)/(2 moles H2)) x ((18.015 g H2O)/(1 mole H2O) =286.07 g H2O
2.63 moles O2 x ((2 moles H2O)/(1 mole O2)) x ((18.015 g H2O)/(1 mole H2O) = 94.76 g H2O
94.76 is the final answer because this is the limiting reactant, meaning it produces less product than the H2 so it limits the reaction from producing anymore product from the amount calculated.
Reducing agent is an compound/atom, that loses an electron and is oxidized.
0.........+I.............+II............0
Ca + 2HCl ----> CaCl₂ + H₂
Calcium is oxidized --- it's reducing agent (reductant).
Hydrogen is reduced --- HCl is oxidizing agent.
The celery and carrot will most likely become saltier and perhaps more shriveled because of the high concentration of salt in the water solution compared to the low concentration of salt in the solution. The raisin, however, could take two roots, one would be the same as the carrot and celery, but the other one is it would soak up water because of how salty and shriveled the raisin already is.
Answer:
3.79 moles
Explanation:
To convert moles to gams of a substance we need to find the molar mass of the substance. For Ca(OH)₂ th molar mass is:
1Ca = 40.08g/mol
2O = 2*16g/mol = 32g/mol
2H = 2*1.01g/mol = 2.02g/mol
The molar mass is:
40.08g/mol + 32g/mol + 2.02g/mol = <em>74.1g/mol</em>
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And moles are:
281g * (1mol / 74.1g) =
<h3>3.79 moles</h3>
