Answer:
The energy decreases as you move from the bottom to the top of the energy pyramid. 90% of the energy entering each step of the pyramid is used up by the consumers, only 10% of the energy get stored. So, when the next level on the pyramid eats them, that 10% gets passed down to them Use the diagram below to answer the question.
Explanation:
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The molecular formula of organic solvent is <em>C6H12</em>
<h2>calculation</h2><h3>find the empirical formula first as in step 1 and 2</h3>
Step 1: f<em>ind the moles of C and H</em>
- moles = % composition/molar mass
- from periodic table molar mass of C= 12 g/mol while that of H= 1 g/mol
- moles is C is therefore = 85.6/12= 7. 13 moles
- moles of H= 14.4/1 - 14.4 moles
Step 2: <em>calculate the mole fraction by dividing each mole by smallest number of mole(7.13)</em>
H= 14.4/7.13 =2
the empirical formula is therefore = CH2
<h2>Then calculate the molecular formula from empirical formula</h2>
step 3: divide the grams molar mass by empirical formula mass
empirical formula mass = 12+(1 x2) = 14 g/mol
= 84.2/ 14 = 6
step 4: multiply each of the subscript within the empirical formula with the value gotten in step 3
- that is [CH2]6 = C6H12 therefore the molecular formula = <u>C6H12</u>
Answer:
16.86%
Explanation:
Na3N is sodium nitride.
% of N = mass of N/ molar mass of Na3N *100
% of N = 14/83*100= 16.86%
Answer:
standard entropy of vaporization of ethanol = 142.105 J/K-mol
Explanation:
given data
enthalpy of vaporization of ethanol = 40.5 kJ/mol = 40.5 × 
J/mol
entropy of vaporization of ethanol boiling point = 285 K
to find out
standard entropy of vaporization of ethanol
solution
we get here standard entropy of vaporization of ethanol that is expess as
standard entropy of vaporization of ethanol ΔS = 
.............1
here ΔH is enthalpy of vaporization of ethanol and T is temperature
put value in equation 1
standard entropy of vaporization of ethanol ΔS = 
standard entropy of vaporization of ethanol = 142.105 J/K-mol
