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liq [111]
4 years ago
9

Explain the process of initiation and elongation.

Chemistry
1 answer:
Alina [70]4 years ago
4 0
Initiation <span>occurs when mRNA, tRNA, and an amino acid meet up inside the ribosome. </span>Elongation occurs when amino acids are continually added to the line, forming a long chain bound together by peptide bonds.
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At night, an equilibrium reaction between two different nitrogen compounds generates N2O5N2O5 in the atmosphere, as represented
kakasveta [241]

The breakdown of NO3 in the day leads to more consumption of N2O5 in the day hence its concentration is greater at night than in the day.

<h3>What is equilibrium constant?</h3>

The equilibrium constant is a number that shows how much reactants are converted to products in a reaction. It is often shown as capital letter K in English.

Given the situation described in the question, we know that the concentration of N205 will be higher at night, because the decomposition of NO3(g) in the daytime will result in an increase in the rate of consumption of N2O5(g) to reform NO3(g).

Learn more about equilibrium constant: brainly.com/question/17960050

3 0
2 years ago
2 C6H14 + 19 O2 --&gt; 12 CO2 + 14 H2O
vivado [14]

Answer:

1.27 moles (3 s.f.)

Explanation:

Mole ratio of water: C6H14

= 14:2

= 7:1

This means that to produce 7 moles of water, 1 mole of C6H14 is needed. Or 1/7 mole of C6H14 is needed to produce 1 mole of water. So if you need 8.86 moles of water, 8.86(1/7) moles of C6H14 is needed.

For 8.86mol of water, moles of C6H14 needed

= 8.86/7

= 1.27 moles (3 s.f.)

4 0
4 years ago
From the list of substances, identify each as a strong acid, strong base, or neither a strong acid nor a strong base.
Dafna11 [192]

Answer:

HNO3 is a strong acid

HCl is also a strong acid

NaCl is a salt so it is neither a strong acid nor a strong base

Ca(OH)3 is a strong base

Explanation:

8 0
3 years ago
what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0
3 years ago
Read 2 more answers
The H 2 produced in a chemical reaction is collected through water in a eudiometer. If the pressure in the eudiometer is 760.0 t
siniylev [52]

Answer:

the pressure (torr) of theH₂ gas is 736.2 torr

Explanation:

Given that

The H₂ gas  produced in a chemical reaction is collected through water in a eudiometer; during this process, the gas collected contains some droplets of water vapor along with these gas.

So; the total pressure in the eudiometer = Pressure in the H₂ gas  - Pressure of the water vapor

Where;

P_{Totsl} =  total pressure in the eudiometer = 760.0 torr

P_{H_2} = Pressure in the H₂ gas  = ???

P_{H_2O} = Pressure in the water vapor  = 23.8 torr

Now:

P_{Totsl} = P_{H_2} + P_{H_2O}

- P_{H_2} = + P_{H_2O} - P_{Totsl}

P_{H_2}  = - P_{H_2O} + P_{Totsl}

P_{H_2}  =  (- 23.8 + 760) torr

P_{H_2}  = 736.2 torr

Thus; the pressure (torr) of theH₂ gas is 736.2 torr

8 0
4 years ago
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