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VikaD [51]
2 years ago
14

How many grams are in 44.8 liters of nitrogen gas, n2? a) 56g b) 27g c) 36g d) 112g

Chemistry
2 answers:
Vlad [161]2 years ago
6 0

Answer:

56 grams

Explanation:

44.8 L = 2 mol

Diatomic nitrogen has a formula mass of 28 g/mol, so 2 moles is 56 grams.

kkurt [141]2 years ago
3 0

a) 56g

<h3>Calculation:</h3>

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = \frac{44.8}{22.4}

                    = 2 mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

#SPJ4

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From the calcuation, the percent ionic character of the bond is  70%

<h3>What is percent ionic character?</h3>

The term percent ionic character has to do with the degree of ionic bonding that is contained in a compound. It can be estimated from the electronegativity of each element.

We can use the formula; 100(1 - e^(-ΔEN² / 4))

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100(1 - e^(-1)^2/4)

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Learn more about percent ionic character:brainly.com/question/7034446

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