Question

How many grams are in 44.8 liters of nitrogen gas, n2? a) 56g b) 27g c) 36g d) 112g

Answer 1

Answer:

56 grams

Explanation:

44.8 L = 2 mol

Diatomic nitrogen has a formula mass of 28 g/mol, so 2 moles is 56 grams.

Answer 2

a) 56g

Calculation:

At STP,

22.4 L of N₂ = 1 mol

We have given 44.8 L of N₂, therefore,

44.8 L of N₂ = $\frac{44.8}{22.4}$

                    = $2$ mol

We know that,

1 mol of N₂ = 28 g

Hence,

2 mol of N₂ = 28 × 2

                   = 56g

Hence, there are 56 g of N₂ in 44.8 L of nitrogen gas.

Learn more about calculation at STP here:

brainly.com/question/9509278

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