Hello!
Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.
We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)
- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)
Both of these act in opposite directions. Let's use the equation for torque:
Doing the summation using their respective lever arms:
Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:
Now, let's solve for 'T'.
Plugging in the values:
Answer:
first minimum distance from the center = 0.417 m m
Explanation:
given,
wavelength (λ) = 506 nm
d = 0.075 mm = 0.000075 m
tanθ = x /2
d sinθ = m λ
m=1 ( 1 st minimum )
0.000075 × sin θ = 506 × 10⁻⁹
sin θ =
sin θ = 0.00675
θ = sin⁻¹(0.00675)
θ = 0.00675
x = 0.000417 m
hence, the first minimum distance from the center = 0.417 m m
Answer:
The velocity
Explanation:
For a mass-spring system, the total mechanical energy is constant during the motion. The total mechanical energy is sum of the elastic potential energy, U, and the kinetic energy, K:
where
k is the spring constant
x is the displacement
m is the mass
v is the velocity
Since E must remain constant, we see that when x increases, v decreases, and vice-versa. Therefore, when x (the displacement) is at maximum, v (the velocity) is at minimum (more precisely, it is zero).