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BigorU [14]
3 years ago
7

In a hydroelectric power plant, 65 m3 /s of water flows from an elevation of 90-m to a turbine-generator, where electricity is g

enerated. if the overall efficiency of the turbine-generator is 84%, determine the electric output of this plant, in mw. neglect all frictional losses, assume that the velocity of the inlet and outlet are small, and assume that both sides of the power plant are exposed to atmospheric pressure.
Physics
1 answer:
Mariulka [41]3 years ago
3 0

The electric output of the plant is 48.19 MW

First we need to calculate the water power, it is given by the formula

WP=ρQgh

Here, ρ=1000 kg/m3 is density of water,Q is the flow rate, g is the gravity, and h is the water head

Therefore, WP=1000*65*9.81*90=57388500 W=57.38 MW

Now the overall efficiency of the hydroelectric power plant is given as

η=\frac{electric power}{water power}

Plugging the values in the above equation

0.84=EP/57.38

EP=48.19 MW

Therefore, the electric output of the plant is 48.19 MW.

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What is your mass in kilograms if you weigh 120 pounds
schepotkina [342]

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then your mass is  329.1 kilograms.

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-- If you weigh 120  pounds on the Earth,
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6 0
3 years ago
When a photon collides with an electron and is deflected, the photon’s ____ decreases.
masha68 [24]

Answer:

2. Wavelength

Explanation:

When a photon collides with an electron and is deflected, the photon’s wavelength decreases.

When photon gained energy by the collision of the electron. Its energy and frequency will be increased and its wavelength will be decreased.

7 0
3 years ago
Read 2 more answers
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

k=29.4 N/m

b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
A block of mass 3. 0 kg is hung from a spring, causing it to stretch 12 cm at equilibrium, as shown above. The 3. 0 kg block is
QveST [7]

Answer: 32 cm

Explanation:

4 0
2 years ago
If an incident light ray hits a flat smooth object at 28 degrees, it will reflect off at an angle of…
Nookie1986 [14]

Option B is correct. If an incident light ray hits a flat, smooth object at 28°. It will reflect off at an angle of 28°.

<h3>What is the law of reflection?</h3>

The law of reflection specifies that upon reflection from a downy surface, the slope of the reflected ray is similar to the slope of the incident ray.

The reflected ray is consistently in the plane determined by the incident ray and perpendicular to the surface at the point of reference of the incident ray.

When the light rays descend on the smooth surface, the angle of reflection is similar to the angle of incidence, also the incident ray, the reflected ray, and the normal to the surface all lie in a similar plane.

If an incident light ray hits a flat, smooth object at 28 degrees, it will reflect off at an angle of 28°.

Hence, option B is correct

To learn more about the law of reflection, refer to the link;

brainly.com/question/12029226

#SPJ1

5 0
2 years ago
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