How much energy is lost through carrying out life functions?

A glass of water sitting in direct sunlight evaporates over time. Explain this phase change in terms of the types of heat transf

dybincka [34]

This is a physical phase change it is still water it just separated and became less and less.it stays water though

5 0

3 years ago

A 0.0795-g sample of magnesium metal reacts with hydrochloric acid to give 88.5 mL of hydrogen gas at 25 degree C and 766 mm Hg.

Trava [24]

Answer:

(a). 0.0037 mol.

(b). 22.42 L

(c). => When the measuring apparatus are not precise.

=> Error due to parallax.

=> Random errors.

Explanation:

Without mincing words let us dive straight into the solution to the question above. So, we are given the following parameters or information which are going to aid in solving this particular Question;

Mass of magnesium given= 0.0795 g, volume of Hydrogen = 88.5 mL = 0.0885 L, temperature = 25 degree C = 273 + 25 = 298K and pressure = 766 mm Hg = 766/760 = 1.00789 atm.

(a). In order to determine the number of moles of Hydrogen atoms,we will be making use of the formula below;

Number of moles = (pressure × Volume)/ gas constant,R × Temperature.

Thus,the number of moles of Hydrogen = 1.00789 × 0.0885 / [( 0.08206 × 298] = 0.0037 mol.

(b). The molar volume at stp can be calculated by using the same formula that was used in (a) above;

Molar Volume at stp = Gas constant,R × temperature/ Pressure = 0.08206 × 273 / 1 atm = 22.42 L.

(c). The major sources of errors are given below:

=> When the measuring apparatus are not precise.

=> Error due to parallax.

=> Random errors.

3 0

3 years ago

50 pts Plz help !!!! What is the physical state of matter of baking soda.

WITCHER [35]

Baking soda is a solid.

8 0

2 years ago

Read 2 more answers

An atom of potassium has 19 protons and 19 electrons. If the atom loses 1 electron, what will

Pani-rosa [81]

｡☆✼★ ━━━━━━━━━━━━━━ ☾

If it loses 1 electron, it will now have 1 more proton than electrons.

Thus, the charge would be 1+

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5 0

3 years ago

g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o

Liono4ka [1.6K]

Answer:

pOH = 0.36

Explanation:

Both potassium hydroxide and lithium hydroxide solutions are strong bases, so you assume 100% dissociation.

1. Potassium hydroxide solution, KOH

Volume, V = 304 mL = 0.304 liter

Molarity, M = 0.36 M

number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol

1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

2. LIthium hydroxide, LiOH

Volume, V = 341 mL = 0.341 liter

Molarity, M = 0.51 M

number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol

1mole of LiOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.17391

3. Resulting solution

Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

4. pOH

$pOH=-\log [OH^-]=-\log (0.439)=0.36$ ← answer

5 0

3 years ago