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Vanyuwa [196]
2 years ago
15

A 7950-kg railroad car travels alone on a level frictionless track with a constant speed of 15.0 m/s . A 2950-kg load, initially

at rest, is dropped onto the car.
What will be the car's new speed?
Express your answer to three significant figures and include the appropriate units.
Physics
1 answer:
Alchen [17]2 years ago
5 0

The new speed of car is 10.9 m/s

<h3 />

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Mass of the railroad car, m₁ = 7950 kg

Mass of the load, m₂ = 2950 kg

It can be assumed as the speed of the car, u₁ = 15 m/s

Initially, it is at rest, u₂ = 0

Let v is the speed of the car. It can be calculated using the conservation of momentum as :

m_1u_1 + m_2u_2 = (m_1 + m_2) v

v =\frac{m_1u_1}{m_1+m_2}

v = \frac{7950*15}{7950+2950}

v= 10.9 m/s

Therefore, the new speed of care is 10.9 m/s

Learn more about momentum here:

brainly.com/question/22257327

#SPJ1

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A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two
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Answer:

a)     L = 33.369 m , b) 21

Explanation:

The analysis of the ocean depth can be performed assuming that at the bottom of the ocean there is a node and the surface must have a belly, so the expression for resonance is

         λ = 4 L / n

         n = 1, 3, 5, ...

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         v = λ f

        v = 4L / n f

        L = n v / 4f

Let's write the expression for the two frequencies

       L = n₁ 343/4 53.95

       L = n₁ 1,589

       

       L = n₂ 343/4 59

       L = n₂ 1.4539

Let's solve the two equations

       n₁ 1,589 = n₂ 1,459

       n₁ / n₂ = 1.4539 / 1.589

       n₁ / n2 = 0.91498

Since the two frequencies are very close the whole numbers must be of consecutive resonances, let's test what values ​​give this value

  n₁    n₂    n₁ / n₂

  1      3       0.3

  3     5       0.6

  5     7        0.7

  7     9        0.77

  9    11        0.8

  17   19       0.89

  19  21        0.905

  21  23       0.913

  23 25       0.92

Therefore the relation of the nodes is n₁ = 21  and n₂ = 23

Let's calculate

                L = n₁ 1,589

                L = 21  1,589

                L = 33.369 m

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