1 because the the mid night summer is dark
B if you make it rougher they won’t be able to have frictions
Answer:
(A) 1.01 s
(B)
Explanation:
horizontal distance (L) = 3 m
vertical height (h) = 1.25 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) hang time refers to how long the person remains in the air, and is the summation of the time it took attain maximum height and the time it takes to get back to the ground.
- it is going to take the same amount of time to attain maximum height and to return to the ground.
- from s = ut + 0.5g we can get the time taken to attain maximum height.
where s = vertical distance = 1.25 m
u = initial velocity = 0 (since body starts from rest)
g = acceleration due to gravity = 9.8 m/s^{2}
t == time taken to get to maximum height
the equation now becomes s = 0.5g
1.25 = 0.5 x 9.8 x
= 1.25/(0.5x9.8)
t =
t = 0.505 s
- now that we have the time taken to attain maximum height which is also equal to the time it takes to get back to the ground.
total time = time taken to attain maximum height + time it takes to get back to the ground.
total time = 0.505 + 0.505 = 1.01 s
(B) when horizontal distance = 6 m , the hang time would remain the same, because the horizontal component does not affect the vertical component . Also we can see that from the equation used in part A above the horizontal component was not used to solve for the time. Therefore hang time = 1.01 s
Explanation:
We need to draw position-time graph when the speed is increasing.
The slope of position-time graph gives the speed of an object.
Position means distance covered.
When the speed of an object is increasing with time. It means it is moving with increasing speed.
The attached figure shows the position -time graph when speed is increasing.
Answer:
<em>The Strength of the electric field produced = 2 × 10⁷ N/C</em>
Explanation:
<em>Electric Field:</em> This is defined as the region where an electric force is experienced.
<em>Electric Field Strength: </em><em>The intensity of an electric field at any point is defined as the force per unit charge which it exert at that point. It direction is that of the force exerted on a positive charge.</em>
<em>It is represented mathematically as,</em>
<em>E = F/Q ................................. Equation 1</em>
<em>Where E = Electric field strength, F = electric force, Q = test charge.</em>
<em>Given: F = 3.2 × 10⁻⁴ N, Q = 1.6 × 10⁻¹¹ C</em>
<em>Substituting these values into equation 1</em>
<em>E= 3.2 × 10⁻⁴/1.6 × 10⁻¹¹ </em>
<em>E= 2 × 10⁷ N/C</em>
<em>Thus the Strength of the electric field produced = 2 × 10⁷ N/C</em>
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