2 years ago

Please help i would really appreciate it

Physics

2 answers:

Verdich [7]2 years ago

4 0

Answer:

THE MINIONSSSSSSS AYEEEEE

Explanation:

Fed [463]2 years ago

4 0

Answer:

Did you try searching it up

Explanation:

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3 years ago

A steel cable has a cross-sectional area 2.54 10-3 m2 and is kept under a tension of 1.01 104 N. The density of steel is 7860 kg

ElenaW [278]

Answer:

The speed is equals to 22.49 m/s

Explanation:

Given Data:

$Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3$

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Solution:

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$p=m/V\\\\ p=m/(L*A)\\p*A=m/L$

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$\sqrt \frac{F*L}{m}\\$

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$\sqrt\frac{1.01*10^4}{7860*2.54*10^-^3} \\$

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