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Zarrin [17]
3 years ago
9

Why doesn't the force of gravity change the speed of a bowling ball as it rolls along a bowling lane?

Physics
1 answer:
Oliga [24]3 years ago
5 0
Because the gravitational force, which points downward, is perfectly balanced by the normal reaction of the floor of the bowling lane, which points upward. The two forces are equal in magnitude, so the net force acting vertically on the bowling ball is zero, therefore there is no acceleration along this direction. Moreover, since the ball is moving in the horizontal direction, the gravitational force has no component along this direction, so it does not change the velocity of the ball.
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Two insulated wires, each 2.64 m long, are taped together to form a two-wire unit that is 2.64 m long. One wire carries a curren
nikklg [1K]

Answer:

4.77\ \text{A}

Explanation:

F = Magnetic force = 4.11 N

I_n = Net current

I_2 = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

\theta = Angle between current and magnetic field = 65^{\circ}

l = Length of wires = 2.64 m

I = Current in the other wire

Magnetic force is given by

F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}

Net current is given by

I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}

The current I is 4.77\ \text{A}.

8 0
3 years ago
A 50 kg bicyclist, traveling at a speed of 12 m/s, applies the brakes, slowing her speed to 3 m/s.
Bezzdna [24]

a) Work done = Net Kinetic Energy

= 1/2 x 50 kg x ((12m/s)^2 - (3m/s)^2)

= 0.5 x 50 Kg x (144 -9)(m/s)^2

= 3375 Kg (m/s)^2

b) Force = mxa

a = 120 N/50 Kg = 2.4 m/s^2

Using newtons third law of motion, we get-

V^2 - U^2 = 2 x a x S

S= (12^2-3^2)m^2/s^2/(2 x 2.4 m/s^2)

= 28.125 m


3 0
4 years ago
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Answer:

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Explanation:

3 0
3 years ago
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A musical chord consists of several notes, each formed by a sound wave of a different frequency. The three graphs show the patte
sweet [91]

Answer:

If a chord had notes with frequencies of 100, 1,000, and 6,000 Hz, the basilar membran would vibrate at multiple positions, with peaks at A, B, and C.

Explanation:

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3 years ago
Please help me. I'll mark brainiest
valkas [14]
1-d 2-a. This is not my field of expertise but this is my assumption
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