What is the magnitude b of the magnetic field at the location of the charge due to the current-carrying wire?
1 answer:
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Answer:
Two moles of aluminum chloride are produced when six miles of hydrogen Chloride
react with plenty of aluminum
Explanation:
6 Moles of will only react with 2 moles of
irrespective of the number of moles of each compound present. The reaction wiil take place in this ratio only. The products produced will be 2 moles of
and 3 moles of
this ratio will also be constant.
So, six moles of hydrogen chloride will react with plenty of aluminum to produce many 2 moles of aluminum chloride
.
Answer:
1.87 A
Explanation:
τ = mean time between collisions for electrons = 2.5 x 10⁻¹⁴ s
d = diameter of copper wire = 2 mm = 2 x 10⁻³ m
Area of cross-section of copper wire is given as
A = (0.25) πd²
A = (0.25) (3.14) (2 x 10⁻³)²
A = 3.14 x 10⁻⁶ m²
E = magnitude of electric field = 0.01 V/m
e = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C
m = mass of electron = 9.1 x 10⁻³¹ kg
n = number density of free electrons in copper = 8.47 x 10²² cm⁻³ = 8.47 x 10²⁸ m⁻³
= magnitude of current
magnitude of current is given as
= 1.87 A