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Alecsey [184]
2 years ago
15

What is the mole fraction of sulfuric acid in a solution made by adding 34 g of sulfuric acid (H2SO4 = 98 g/mol) to 100 g of wat

er (H2O = 18 g/mol)?
Chemistry
1 answer:
sladkih [1.3K]2 years ago
7 0

Answer:

Mole Fraction  =  0.059

Explanation:

To find the mole fraction, you need to (1) convert grams H₂SO₄ and H₂O to moles (via molar mass) and then (2) calculate the mole fraction.

(Step 1)

Molar Mass (H₂SO₄): 98 g/mol

34 grams H₂SO₄            1 mole
--------------------------  x  -------------------  =  0.347 moles H₂SO₄
                                      98 grams

Molar Mass (H₂O): 18 g/mol

100 grams H₂O              1 mole
-------------------------  x  --------------------  =  5.56 moles H₂O
                                      18 grams

(Step 2)

                                             moles solute
Mole Fraction  =  -------------------------------------------------
                               moles solute + moles solvent

                                              0.347 moles H₂SO₄
Mole Fraction  =  -----------------------------------------------------------
                               0.347 moles H₂SO₄ + 5.56 moles H₂O

Mole Fraction  =  0.059

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6 0
3 years ago
Which of the following is an example of a chemical reaction?
nevsk [136]

Answer:

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3 0
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1. It is the place near the coast where sea water and fresh water mixes and is called “nurseries
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Explanation:

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4 0
2 years ago
The half-life of sr-90 is 28 years. after 56 years of decay only 0. 40 g of a sample remains. what was the mass of the original
Svetradugi [14.3K]

Half-life is the time taken for the concentration of the substance to reduce by 50%. The original sample of strontium had a mass of 1.6 gms. Thus, option d is correct.

<h3>What is half-life?</h3>

The half-life of any radioactive substance is the time period at which the concentration will get reduced to half the initial amount. The initial mass of Sr-90 is calculated as,

N(t) = N_{0} (\dfrac{1}{2})^{ \frac{t }{t 1/2}}

Given,

Quantity of the remaining substance N (t) = 0.40 gm

Initial radioactive substance quantity N_{0} =?

Time duration (t) = 56 years

Half-life = 28 years

Substituting values above:

\begin{aligned} 0.40 &= N_{0} (\dfrac{1}{2}) ^{{\frac{56}{28}}\\\\0.40 &= N_{0} (\dfrac{1}{2})^{2}\end{aligned}

= 1.6 gm

Therefore, option d. the initial mass of Sr is 1.6 gm.

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7 0
2 years ago
How do scientists describe the behavior of particles in solids and plasmas?
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Answer:

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Explanation:

8 0
4 years ago
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