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2 years ago

If you are given 0.25 mol of Fe and 0.5 mol of O2, what is the limiting reactant?

Chemistry

2 answers:

erik [133]2 years ago

8 0

The limiting reactant from the calculations is Fe.

<h3>What is the limiting reactant?</h3>

The limiting reactant is the reactant that is present in the least amount in solution. Now we have the equation as; 4Fe+ 3O2 → 2Fe2O3

If 4 moles of Fe reacts with 3 moles of O2

0.25 mol of Fe reacts with 0.25 mol * 3 moles/4 moles

= 0.1875 moles of O2

It then follows that the limiting reactant is Fe.

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jeka942 years ago

6 0

The limiting reactant will be Fe.

<h3>What are limiting reactants?</h3>

They are reactants that are available in limited quantities, as compared to other reactants, during the course of reactions.

From the equation of the reaction: $4Fe + 3O_2 --- > 2Fe_2O_3$

The mole ratio of Fe to O2 is 4:3.

Thus, for 0.25 mol Fe, 0.25 x 3/4 = 0.1875 mol of O2 is required.

With 0.5 mol of O2 available, it means oxygen is in excess while Fe is limited in availability.

More on limiting reactants can be found here: brainly.com/question/14225536

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