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Cerrena [4.2K]
3 years ago
8

Calculate the molar mass of aluminum oxide (Al2O3). Express your answer to four significant figures.

Chemistry
1 answer:
NISA [10]3 years ago
5 0

Answer:

102.0 g/mol

Explanation:

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Law Incorporation [45]
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2 years ago
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How many moles of oxygen are required to produce 37.15 g CO2? 37.15 g CO2 = mol O2
NNADVOKAT [17]

Answer:

0.84 moles of oxygen are required.

Explanation:

Given data:

Mass of CO₂ produced = 37.15 g

Number of moles of oxygen = ?

Solution:

Chemical equation:

C + O₂     →     CO₂

Number of moles of  CO₂:

Number of moles = mass/molar mass

Number of moles = 37.15 g/ 44 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of oxygen and carbon dioxide.

                          CO₂         :       O₂  

                              1           :         1

                            0.84       :       0.84

0.84 moles of oxygen are required.

6 0
3 years ago
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I don’t know how to solve this
stepladder [879]
Hi,

Answer is 191.2.

800J = 191.2 cal

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Answer:

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Elements join together to form_____.
sineoko [7]

Answer:

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Explanation:

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