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boyakko [2]
1 year ago
8

When attempting to recover your primary second stage underwater, it is acceptable to switch to your alternate air source while y

ou search for your primary. Select one: True False
Physics
1 answer:
icang [17]1 year ago
7 0

During primary second stage underwater recovery, it is acceptable to switch to your alternate air source while you search for your primary which makes it a true statement.

<h3>What is Primary second stage underwater?</h3>

This involves the intermediate pressure air from the regulator hose being taken and reduced to ambient pressure.

Switching to your alternate air source  will ensure that the diver breathe safely which is why True was chosen.

Read more about Primary second stage underwater here brainly.com/question/17315714

#SPJ1

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What energy transfer will a stretched rubber band have when let go
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Answer:

when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)

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2 years ago
An object is 50 cm from a converging lens with a focal length of 40 cm . A real image is formed on the other side of the lens, 2
Leno4ka [110]

Answer:

d) -4.0

Explanation:

The magnification of a lens is given by

M=-\frac{q}{p}

where

M is the magnification

q is the distance of the image from the lens

p is the distance of the object from the lens

In this problem, we have

p = 50 cm is the distance of the object from the lens

q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct

Also, q is positive since the image is real

So, the magnification is

M=-\frac{200 cm}{50 cm}=-4.0

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3 years ago
On a velocity time graph, the slope tells you the ______ of the object.
Paraphin [41]
The acceleration is the correct answer
7 0
3 years ago
A magnifying glass is an example of which type of microscope?
gogolik [260]

A magnifying glass is a simple microscope
5 0
3 years ago
Read 2 more answers
A supertanker ( = 1.70 × 108 kg) is moving with a constant velocity. Its engines generate a forward thrust of 7.40 × 105 N. Dete
a_sh-v [17]

Answer:

(a) 0 (b) F=1.67\times 10^9\ N

Explanation:

Given that,

Mass of a supertanker, m=1.7\times 10^8\ kg

The engine of a generate a forward thrust of, F=7.4\times 10^5\ N

(a) As the supertanker is moving with a constant velocity. We need to find the magnitude of the resistive force exerted on the tanker by the water. It is given by :

F = ma, a is the acceleration

For constant velocity, a = 0

So, F = 0

(b) The magnitude of the upward buoyant force exerted on the tanker by the water is equal to the weight of the ship.

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F=1.7\times 10^8\times 9.8\\\\F=1.67\times 10^9\ N

Hence, this is the required solution.

4 0
2 years ago
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