To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that
F = ma
Where,
m = mass
a = Acceleration (Gravitational acceleration when there is action over the object of the earth)
Torque, as we know, is the force applied at a certain distance, that is,
Where
F= Force
d = Distance
Our values are given as,
Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say
Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is
Answer:
The acceleration of the plane is 10.93 m/s² at that instant.
Explanation:
Given:
Mass of aircraft, 
Downward thrust produced, 
Upward resistance force by air, 
Weight of the aircraft acting donward, 
According to Newton's second law, net force acting on an object is equal to the product of mass and its acceleration.
Here, the net force is given as the difference of downward forces and upward forces.
Now,
Therefore, the acceleration of the plane is 10.93 m/s² at that instant.
Freezing point of the water is known as 273 K
Hope this helps!
Answer:
<h2>11.6 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
mass is in kg
1000 g = 1 kg
145 g = 0.145 kg
From the question we have
force = 0.145 × 80
We have the final answer as
<h3>11.6 N</h3>
Hope this helps you
