The question is incomplete. The complete question is :
C. Balance these fossil-fuel combustion reactions. (1 point)
C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat
CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat
Solution :
C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat
When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.
CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat
When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.
C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat
When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.
C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat
When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.
Answer:
2hrs
Explanation:
Given parameters:
Top speed of the jet = 4500km/hr
Distance = 3000km
Unknown:
Time it will take = ?
Solution:
Velocity is the displacement divided by time.
Velocity =
Time =
The jet flies at one - third its maximum speed;
So, speed of the jet =
x 4500 = 1500km/hr
Time =
= 2hrs
Answer:
1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.
2nd step :To get B from the solution, filter the mixture and get B
3rd step : To get A from the solution evaporate the new solution
Explanation:
Assuming 2mg of impurity B to be present
100 mg of A is present as well
<u>Method of purifying A given that B is of same solubility </u>
Dissolve the 100 mg of A with 30 mL
1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.
2nd step :To get B from the solution, filter the mixture and get B
3rd step : To get A from the solution evaporate the new solution
Answer:

Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Data:
We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.
M_r: 65.38
Zn + 2HCl ⟶ ZnCl₂ + H₂
m/g: 12.7
V/mL: 5.00×10²
c/mol·L⁻¹: 1.450
2. Moles of each reactant
(a) Moles of Zn

(b) Moles of HCl
V = 5.0× 10² mL = 0.5000 L

3. Identify the limiting reactant
Calculate the moles of ZnCl₂ obtained from each reactant
(i) From Zn
The molar ratio is 1 mol ZnCl₂:1 mol Zn

(ii) From HCl
The molar ratio is 1 mol ZnCl₂:2 mol HCl

Zinc is the limiting reactant, because it produces fewer moles of ZnCl₂.
4. Moles of HCl reacted
The molar ratio is 2 mol HCl:1 mol Zn

5. Moles of HCl remaining
n = 0.7250 - 0.3885 = 0.3365 mol HCl
6. Concentration of hydrogen ions
The HCl is completely dissociated.

B. compound a material that contains three elements joined in a fixed proportion