How many significant figures in 100000 g?

C. Balance these fossil-fuel combustion reactions. (1 point)

storchak [24]

The question is incomplete. The complete question is :

C. Balance these fossil-fuel combustion reactions. (1 point)

C8H18(g) + 12.5O2(g) → ____CO2(g) + 9H2O(g) + heat

CH4(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

C3H8(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

C6H6(g) + ____O2(g) → ____CO2(g) + ____H2O(g) + heat

Solution :

C8H18(g) + 12.5O2(g) → __8__CO2(g) + 9H2O(g) + heat

When 1 part of octane reacts with 12.5 parts of oxygen, it gives 8 parts of carbon dioxide and 9 parts of water along with liberation of energy.

CH4(g) + __2__O2(g) → __1__CO2(g) + __2__H2O(g) + heat

When 1 part of methane reacts with 2 parts of oxygen, it gives 1 part of carbon dioxide and 2 parts of water along with liberation of energy.

C3H8(g) + __5__O2(g) → __3__CO2(g) + __4__H2O(g) + heat

When 1 part of propane reacts with 5 parts of oxygen, it gives 3 part of carbon dioxide and 4 parts of water along with liberation of energy.

C6H6(g) + __1/2__O2(g) → __6__CO2(g) + __3__H2O(g) + heat

When 1 part of propane reacts with 1/2 parts of oxygen, it gives 6 part of carbon dioxide and 3 parts of water along with liberation of energy.

5 0

3 years ago

A supersonic jet is flying west at one-third of its maximum speed. The jet's top speed is 4,500 kilometres per hour. If the jet'

lana [24]

Answer:

2hrs

Explanation:

Given parameters:

Top speed of the jet = 4500km/hr

Distance = 3000km

Unknown:

Time it will take = ?

Solution:

Velocity is the displacement divided by time.

Velocity = $\frac{displacement}{time}$

Time = $\frac{displacement}{velocity }$

The jet flies at one - third its maximum speed;

So, speed of the jet = $\frac{1}{3}$ x 4500 = 1500km/hr

Time = $\frac{3000}{1500}$ = 2hrs

7 0

3 years ago

if B is completely insoluble in water. Your description should include the volume of solvent required.6b) Assuming that 2 mg of

Misha Larkins [42]

Answer:

1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.

2nd step :To get B from the solution, filter the mixture and get B

3rd step : To get A from the solution evaporate the new solution

Explanation:

Assuming 2mg of impurity B to be present

100 mg of A is present as well

<u>Method of purifying A given that B is of same solubility </u>

Dissolve the 100 mg of A with 30 mL

1st step : mix the mixture with water that way A will dissolve while B will remain insoluble.

2nd step :To get B from the solution, filter the mixture and get B

3rd step : To get A from the solution evaporate the new solution

8 0

2 years ago

Zinc dissolves in hydrochloric acid to yield hydrogen gas: Zn(s) + 2HCl(aq) --> ZnCl2(aq) + H2(g) When a 12.7 g chunk of zinc

ollegr [7]

Answer:

$\boxed{\text{0.673 mol/L}}$

Explanation:

We are given the amounts of two reactants, so this is a limiting reactant problem.

1. Data:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.

M_r: 65.38

Zn + 2HCl ⟶ ZnCl₂ + H₂

m/g: 12.7

V/mL: 5.00×10²

c/mol·L⁻¹: 1.450

2. Moles of each reactant

(a) Moles of Zn

$n = \text{12.7 g Zn} \times \dfrac{\text{1 mol Zn}}{\text{65.38 g Zn}} = \text{0.1942 mol Zn}$

(b) Moles of HCl

V = 5.0× 10² mL = 0.5000 L

$n = \text{0.5000 L HCl}\times \dfrac{\text{1.450 mol HCl}}{\text{1 L HCl}} = \text{0.7250 mol HCl}$

3. Identify the limiting reactant

Calculate the moles of ZnCl₂ obtained from each reactant

(i) From Zn

The molar ratio is 1 mol ZnCl₂:1 mol Zn

$n = \text{0.1942 mol Zn} \times \dfrac{\text{1 mol ZnCl}_{2}}{\text{1 mol Zn}} = \text{0.1942 mol ZnCl}_{2}$

(ii) From HCl

The molar ratio is 1 mol ZnCl₂:2 mol HCl

$n = \text{0.7250 mol HCl} \times \dfrac{\text{1 mol ZnCl}_{2}}{\text{2 mol HCl}} = \text{0.3625 mol ZnCl}_{2}$

Zinc is the limiting reactant, because it produces fewer moles of ZnCl₂.

4. Moles of HCl reacted

The molar ratio is 2 mol HCl:1 mol Zn

$n = \text{0.1942 mol Zn} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Zn}} = \boxed{\text{0.3885 mol HCl}}$

5. Moles of HCl remaining

n = 0.7250 - 0.3885 = 0.3365 mol HCl

6. Concentration of hydrogen ions

The HCl is completely dissociated.

$c = \dfrac{\text{0.3365 mol}}{\text{0.5000 L}} = \textbf{0.673 mol/L}\\\\\text{The concentration of hydrogen ions is $\boxed{\textbf{0.673 mol/L}}$}$

4 0

3 years ago

If a material contains three elements but not joined in a fixed proportion, it is a(an) A. mixture. B. compound. C. atom. D. non

BartSMP [9]

B. compound a material that contains three elements joined in a fixed proportion

7 0

3 years ago

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