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babunello [35]
1 year ago
12

The watermark can be of different types depending on the application. A watermark will resist manipulations of the media. Howeve

r, a watermark will not resist tampering.
Physics
1 answer:
Marina86 [1]1 year ago
7 0

<em>The first blank is </em><em>robust watermark</em>; a robust watermark will not resist tampering.

<em>The second blank is </em><em>fragile watermark</em><em>;</em> a fragile watermark will resist manipulations of the media.

<h3>What is a watermark?</h3>

A watermark is a faint design made in paper during manufacture that is visible when held against the light and clearly identifies the maker.

The watermark can be of different types depending on the application and they include:

  • A robust watermark will not resist tampering.
  • A fragile watermark will resist manipulations of the media.

Thus, The first blank is robust watermark; a robust watermark will not resist tampering.

The second blank is fragile watermark; a fragile watermark will resist manipulations of the media.

Learn more about watermark here:.

brainly.com/question/24206908

#SPJ1

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Decribe what must happen inside of an aluminum can in order for it to be attracted to a positively-charged and to a negatively-c
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Two charges, qA and qB, are separated by a distance, d, and exert a force, F, on each other. Analyze Coulomb's law and answer th
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1/4*(F)

c. 1/9*(F)

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e. F reduces 3/4*(F)

Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is

F = k*(qA*qB)/d²

a. If qA is doubled therefore the force is doubled since they are directly proportional.

b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4

Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.

c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9

d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4

e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,

3/4*F

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