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Iteru [2.4K]
3 years ago
7

29. If you traveled to Mars, your mass would be than your mass on Earth. *

Physics
2 answers:
marin [14]3 years ago
8 0
Yes it would be the same your weight would change:)
Bingel [31]3 years ago
8 0

If you traveled to Mars, your mass would be exactly, precisely equal to your mass on Earth, PROVIDED you did not relieve the boredom of space travel by eating too many astronaut steaks along the way.

The only things that can affect your mass are your personal diet, exercise, sleep, and stress habits.  

Your mass has nothing to do with gravity. Your WEIGHT has.

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A projectile is fired vertically from Earth's surface with an initial speed v0. Neglecting air drag, how far above the surface o
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This may helpv^2=u^2+2as. v=0 at top of flight. a=acceleration of gravity(vo^2)/2a=s.
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3 years ago
How far from the base of the platform does she land?
seropon [69]

When Janet leaves the platform, she's moving horizontally at 1.92 m/s.  We assume that there's no air resistance, and gravity has no effect on horizontal motion.  There's no horizontal force acting on Janet to make her move horizontally any faster or slower than 1.92 m/s.

She's in the air for 1.1 second before she hits the water.

Moving horizontally at 1.92 m/s for 1.1 second, she sails out away from the platform

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3 years ago
Explain how we can deduce the temperature of a star by determining its color.
ValentinkaMS [17]

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7 0
2 years ago
A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance trave
Svetradugi [14.3K]

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation;

a = \frac{6 - 0}{6}

a = \frac{6}{6}

Acceleration, a = 1m/s²

<u>To find the distance covered in the first phase;</u>

<em>Solving for distance, we would use the second equation of motion;</em>

S = ut + \frac {1}{2}at^{2}

<em>Substituting the values into the equation;</em>

S = 0(6) + \frac {1}{2}*1*(6)^{2}

S = 0 + \frac {1}{2}*1*36

S = 0.5 *36

Distance, S1 = 18m

<u>For the second phase, time T2 = 5 secs;</u>

<em>Mathematically, speed is given by the equation;</em>

Speed = \frac{distance}{time}

<em>Making distance the subject of formula, we have;</em>

Distance, S = speed * time

<em>Substituting into the above equation;</em>

Distance, S = 6 * 5

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

<em>Therefore, the total distance traveled by the biker is 48m.</em>

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3 years ago
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