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Nimfa-mama [501]
3 years ago
8

A plastic circular loop has radius R, and a positive charge q is distributed uniformly around the circumference of the loop. The

loop is then rotated around its central axis, perpendicular to the plane of the loop, with angular speed v. If the loop is in a region where there is a uniform magnetic field B S directed parallel to the plane of the loop, calculate the magnitude of the magnetic torque on the loop.
Physics
1 answer:
bearhunter [10]3 years ago
4 0

Answer:

\tau = \frac{q\omega R^2 B}{2}

Explanation:

As we know that charge is uniformly distributed on the circumference of the circular loop

so here we have

total charge = q

also we know that loop is moving with uniform angular speed

angular speed = \omega

now we know that current in the loop due to motion of the ring is given as

i = \frac{q}{T} = \frac{q\omega}{2\pi}

now the magnetic moment of the loop is given as

M = i A

M = (\frac{q\omega}{2\pi})\pi R^2

M = \frac{q\omega R^2}{2}

now we know that the torque on the loop is given as

\tau = \vec M \times \vec B

\tau = MBsin90

\tau = \frac{q\omega R^2 B}{2}

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Help me find the acceleration
ANEK [815]

a = 3.09 m/s²

<h3>Explanation</h3>

This question doesn't tell anything about how long it took for the car to go through 105 meters. As a result, the <em>timeless </em>suvat equation is likely what you need for this question.

In the <em>timeless</em> suvat equation,

a = \dfrac{v^2 - u^2}{2\; x}

where

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  • v is the <em>final</em> velocity of the car;
  • u is the <em>initial</em> velocity of the car; and
  • x is the displacement of the car.

Note that <em>v</em> and <em>u</em> are velocities. Make sure that you include their signs in the calculation.

In this question,

  • a is the unknown;
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  • x = - 105 \; \text{m}.

Apply the <em>timeless</em> suvat equation:

a = \dfrac{v^{2} - u^{2}}{2\; x}\\\phantom{a} = \dfrac{(-10.9)^{2} - (-27.7)^{2}}{2 \times (-105)}\\\phantom{a} = 3.09 \; \text{m} \cdot \text{s}^{-2}.

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A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 12 A, while that
andreev551 [17]

Answer:

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b) 564watts

c) 1.11

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Power consumed = IV

I is the current rating

V is the operating voltage

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c) Energy used = Power consumed × time taken

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