Answer:
The limiting reactant is H₂
Explanation:
The reaction of hydrogen (H₂) and carbon monoxide (CO) to produce methanol (CH₃OH) is the following:
2H₂(g) + CO(g) → CH₃OH(g)
From the balanced chemical equation, we can see that 1 mol of CO reacts wIth 2 moles of H₂. So, the stoichiometric ratio is:
2 mol H₂/1 mol CO = 2.0
We have 500 mol of CO and 750 mol of H₂, so we calculate the ratio to establish a comparison:
750 mol H₂/500 mol CO = 1.5
Since 2.0 > 1.5, we have fewer moles of H₂ than are needed to completely react with 500 moles of CO. In fact, we need 1000 moles of H₂ and we have 750 moles. So, the limiting reactant is H₂.
Colligative properties include lowering the freezing point, lowering the vapor pressure, and raising the boiling point.
Answer:
The volume of a gas approaches zero as the temperature approaches absolute zero.
Step-by-step explanation:
You may have done a <em>Charles' Law experiment</em> in the lab, in which you measured the volumes of a gas at various temperatures.
You plotted them on a graph, and perhaps you were asked to extrapolate the graph to lower temperatures.
Your graph probably looked something like the one below.
There is clearly an x-intercept at some low temperature.
Inference: The volume of a gas approaches zero as the temperature approaches absolute zero.
Answer:
Explanation:
Cadmium:(Cd)
Cadmium is transition metal present in group twelve. It is soft metal and properties are similar to the other group members like zinc and mercury. Its atomic number is forty eight and have two valance electrons.
Electronic configuration:
Cd₄₈ = [Kr] 4d¹⁰ 5s²
Vanadium: (V)
It is present in group five. It is malleable and ductile transition metal. Its atomic number is twenty three. Vanadium have five valance electrons.
Electronic configuration:
V₂₃ =[Ar] 3d³ 4s²
Xenon: Xe
Xenon is present in group eighteen. It is noble gas. Its outer most valance shell is complete that's why it is inert. its atomic number is fifty four. Xenon have eight valance electrons.
Electronic configuration:
Xe₅₄ = [Kr] 4d¹⁰ 5s² 5p⁶
Iodine: (I)
Iodine is present in group seventeen. Its outer most valance shell have seven electrons. Iodine is the member of halogen family. It gain one electron to complete the octet. its atomic number is fifty three.
Electronic configuration:
I₅₃ = [Kr] 4d¹⁰ 5s² 5p⁵
Potassium: (K)
Potassium is present in group one. it is alkali metal. Its atomic number is nineteen. Its valance shell has one electron. Potassium loses its one valance electron and gets stable electronic configuration.
Electronic configuration:
K₁₉ = [Ar] 4s¹
Strontium: Sr
Strontium is present in group two. it is alkaline earth metal. its atomic number is thirty eight and have two valance electrons.
Electronic configuration:
Sr₃₈ = [Kr] 5s²
