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Ksenya-84 [330]
1 year ago
9

A 3.82 g piece of limestone contains 2.62 g of CaCO3

Chemistry
1 answer:
Kobotan [32]1 year ago
7 0

Considering the definition of percentage by mass, the mass percentage of CaCO₃ is 68.59%.

<h3>What is mass percentage</h3>

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

mass percentage=\frac{mass of solute}{mass of solution}x100

<h3>Mass percentage of CaCO₃</h3>

In this case, you know:

  • mass of CaCO₃: 2.62 grams
  • mass of limestone: 3.82 grams

Replacing in the definition of mass percentage:

mass percentage=\frac{2.62 grams}{3.82 grams}x100

<u><em>mass percentage= 68.59 %</em></u>

Finally, the mass percentage of CaCO₃ is 68.59%.

Learn more about percentage by mass:

brainly.com/question/24201923

brainly.com/question/9779410

brainly.com/question/17030163

#SPJ1

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0.086mole

Explanation:

The problem is very simple. It involves conversion from mass to number of moles of NaCl

What is mole?

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How is it related and can be converted from mass;

 

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How many grams of Na2SO4 can be produced from 423.67 g of NaCl?
san4es73 [151]

Mass of  Na2SO4= 514.18 grams

<h3>Further explanation</h3>

Given

423.67 g of NaCl

Required

mass of  Na2SO4

Solution

Reaction

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