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Contact [7]
4 years ago
12

A couple is planning to have a child. the father-to-be has six fingers, a dominant trait. His genotype is Ff. His wife has five

fingers. What are the odds that their child will have six fingers? A. 1/4 B. 7/8 C. 1/2 D. There is not enough information.​
Chemistry
1 answer:
postnew [5]4 years ago
4 0
I think it’s C.1/2 because the child could get five fingers like his mother or six fingers like his dad
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Create a chart that compares physical and chemical properties. Give two examples for each type of property
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<em>Answer:</em>

<em>Chemical properties:</em>

Those properties which change the chemical nature of matter.

<em>Example:</em>  

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<em>Physical properties:</em>

Those properties which do not change the chemical nature of matter.

<em>Example</em>

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  • M.P
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<em>Differences between chemical and physical properties:</em>

       Chemical properties                                       Physical properties

1. Observed after the change bringing           1. Observed with out being

the change                                                            change

2. These changes the molecules                    2. only change physical state

3. Chemical identity changes                          3.Chemical identity not changes

4. Structure of material changes                     4.Structure of material not change            

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3 years ago
The reaction of methane with water to form carbon dioxide and hydrogen is nonspontaneous at 298 K. At what temperature will this
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Answer:

The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.

Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.

Explanation:

CH4(g) + 2H2O(g) ⇆ CO2(g) + 4H2(g)

CH4(g) H2O(g) CO2(g) H2(g) ΔH°f (kJ/mol): –74.87 –241.8 –393.5 0

ΔG°f (kJ/mol): –50.81 –228.6 –394.4 0

S°(J/K·mol): 186.1 188.8 213.7 130.7

ΔG<0 to be spontaneous

ΔG = ΔH- TΔS <0

ΔH = ∑nΔH(products) - ∑nΔH(reactant)

ΔH = (-393.5) - (–74.87 + 2*–241.8)

ΔH = 164.97 kJ = 164970 J

ΔS = ∑nΔS(products) - ∑nΔS(reactant)

ΔS = (213.7 + 4*130.7) - (186.1 + 2*188.8)

ΔS = 172.8 J

0 > 164970 J - T* 172.8 J

-164970 J > - T* 172.8 J

954.7< T

The system makes the transition from nonspontaneous to spontaneous at a temperature of 954.7 K.

Under 954.7 K the reaction is nonspontaneous; more than 954.7 K is the reaction spontaneous.

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