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NISA [10]
1 year ago
6

Most foods that are high in calcium are poor sources of iron. this statement illustrates the characteristic of a nutritious diet

known as _____.
Chemistry
1 answer:
natka813 [3]1 year ago
6 0

Most foods that are high in calcium are poor sources of iron. this statement illustrates the characteristic of a nutritious diet known as balance.

Nutrition is the biochemical and physiological processes by which organisms use food to sustain life. It provides organisms with nutrients that can be metabolized to produce energy and chemical structures. An inadequate supply of nutrients leads to malnutrition.

Although these two definitions may seem similar, there are differences. Health simply means food that protects you from disease and keeps you alive. Nutrient-rich foods mean foods that provide sufficient nutrients (vitamins, carbohydrates, proteins) that the body needs to survive the kind that is either low in fiber or high in fat, salt, and/or sugar. Eating too much food or drink.

Learn more about   nutritious  here

https://brainly.in/question/25409994

#SPJ4

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How, exactly, would altering the pH in a solution affect a living organism and how do organisms prevent large pH fluctuations?
oksano4ka [1.4K]

Answer:

pH solutions cause the water to become more basic or more acidic therefore would force the organisms to adapt to their new situations

4 0
3 years ago
If a concentration of 10 fluorescent molecules per μm2of cell membrane is needed to visualize a cell under the microscope, how m
lara [203]

Answer : Total molecules that will be needed to visualize a single egg will be 78500 molecules of dye.

Explanation : As a single egg cell has an approximately diameter of 100 μm.

We can use this formula to calculate area of the cell membrane;

A = π (100)^{2} / 4;  

We can take π as 3.14 and we get;

A = 3.14 X (100)^{2} / 4  

Soving we get;

A =  7850 μm^{2}  

Here we have to calculate the amount of dye molecules which will be needed for 10 fluorescent molecules / μm^{2}  but;

here 1 μm^{2} = 7850 μm^{2} dye molecules.

Therefore, 10 fluorescent molecules will need;  

7850 X 10 = 78500 molecules of dye.

Therefore, the answer is 78500 molecules of dye.

6 0
3 years ago
HELP ASAP
Bezzdna [24]
A. I think sorry if it’s wrong
5 0
3 years ago
How many moles of CaCO3 are needed to react with 12.5 mol SO2​
grandymaker [24]
<h3><u>Answer;</u></h3>

= 12.5 Moles of CaSO3

<h3><u>Explanation</u>;</h3>

The reaction between CaCO3 and SO2 is given by the equation.

CaCO3(s) + SO2(g) → CaSO3(aq) + CO2(g)

The mole ratio between CaCO3 and SO2 is 1 : 1;

1 mole of CaCO3 reacts with 1 mole SO2 to form CaSO3 and CO2

Therefore;

<em>12.5 moles of SO2 will require 12.5 moles of CaSO3</em>

7 0
3 years ago
A sample originally contained 1.28 g of a radioisotope. It now contains 1.12 g of its daughter isotope.
dexar [7]
The answer is 3.

<span>The relation between number of half-lives (n) and decimal amount remaining (x) can be expressed as:

</span>(1/2) ^{n} =x

We need to calculate n, but we need x to do that. To calculate what p<span>ercentage of a radioactive species would be found as daughter material, we must calculate what amount remained:
1.28 -</span> 1.12 = 0.16

If 1.28 is 100%, how much percent is 0.16:
1.28 : 100% = 0.16 : x
x = 12.5% 
Presented as decimal amount:
x = 0.125


Now, let's implement this in the equation: 

<span>(1/2) ^{n} =0.125
</span>
Because of the exponent, we will log both sides of the equation:
n * log(1/2) = log(0.125)
n = \frac{log(0.125)}{log(1/2)}
<span>n = \frac{log(0.125)}{log(0.5)}
</span>n= \frac{-0.903}{-0.301}
n = 3

Therefore, 3 half-lives have passed <span> since the sample originally formed.</span>
4 0
3 years ago
Read 2 more answers
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