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3 years ago

Which polyatomic ion is found in the compound represented by the formula NaHCO3?

Chemistry

2 answers:

stiv31 [10]3 years ago

8 0

Answer: The correct option is 2.

Explanation: Polyatomic ions are defined as the ions in which two or more elements are covalently bonded to act as a single unit. They always carry some charge.

Examples of polyatomic ions are: $OH^-$ known as hydroxide ion, $SO_4^{2-}$ known as sulfate ion

We are given a compound $NaHCO_3$ having 2 ions which are $Na^+$ and $HCO_3^-$ . these ions are named as sodium ions and hydrogen carbonate ions.

Therefore, the correct option is 2.

Annette [7]3 years ago

7 0

The correct answer is option 2. Hydrogen carbonate is the polyatomic ion in the compound given. A polyatomic ion is a charged species composed of covalently bonded atoms. Hydrogen carbonate, also known as bicarbonate, is a polyatomic ion with the charge of -1.

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⦁ Find the concentration of H+, OH-, PH and POH of 0.03 M of magnesium hydroxide which ionizes to the extent of only 1 /3 in aqu

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Answer:

$pH=12.3\\\\pOH=1.7\\$

$[H^+]=5x10^{-13}M$

$[OH^-]=0.02M$

Explanation:

Hello there!

In this case, according to the given ionization of magnesium hydroxide, it is possible for us to set up the following reaction:

$Mg(OH)_2(s)\rightleftharpoons Mg^{2+}(aq)+2OH^-(aq)$

Thus, since the ionization occurs at an extent of 1/3, we can set up the following relationship:

$\frac{1}{3} =\frac{x}{[Mg(OH)_2]}$

Thus, x for this problem is:

$x=\frac{[Mg(OH)_2]}{3}=\frac{0.03M}{3}\\\\x= 0.01M$

Now, according to an ICE table, we have that:

$[OH^-]=2x=2*0.01M=0.02M$

Therefore, we can calculate the H^+, pH and pOH now:

$[H^+]=\frac{1x10^{-14}}{0.02}=5x10^{-13}M$

$pH=-log(5x10^{-13})=12.3\\\\pOH=14-pH=14-12.3=1.7$

Best regards!

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