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shusha [124]
3 years ago
8

A student designs an experiment where he takes a small wood car with 1.0 inch diameter wheels and rolls it down a ramp. The stud

ent measures the speed of the car when it reaches the bottom of the ramp. The student then takes a small plastic car with 1.5 inch diameter wheels and repeats the process. Finally, the student takes a small metal car with 2.0 inch diameter wheels and repeats the process a final time. The student notes that the metal car had the fastest speed at the bottom of the ramp.
The student can conclude:
Chemistry
2 answers:
aleksley [76]3 years ago
8 0
The metal car airodinamics with body style and weight increased speed
Anastaziya [24]3 years ago
3 0

Answer:

As the radius of a wheel , in rolling motion on a inclined plane, changes , its final speed , does not change . In other words , acceleration of wheel on inclined plane does not depend upon radius of the wheel . It also does not depend upon the mass of the wheel.

Explanation:

In case of perfect rolling on an inclined plane, the acceleration of body is given by the following expression.

a = g/1+k²/r² where k is known as radius of gyration . For a wheel its value is equal to( 1/√2)r.r is radius . From this expression , one can conclude that acceleration and therefore velocity does not depend upon radius of the wheel . Therefore the reason of the metal car having greatest speed  is the resistance of air and friction of surface being the least in its case.

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A tire at 21°c has a pressure of 0.82 atm. its temperature decreases to –3.5°c. if there is no volume change in the tire, what i
rjkz [21]

The pressure of the tyre after the temperature change is 0.89atm. Details about pressure can be found below.

<h3>How to calculate pressure?</h3>

The pressure of the tyre can be calculated using the following equation:

P1/T1 = P2/T2

Where;

  • P1 = initial pressure
  • P2 = final pressure
  • T1 = initial temperature
  • T2 = final temperature

According to this question, a tyre at 21°C (294K) has a pressure of 0.82 atm. Its temperature decreases to –3.5°C (269.5K).

0.82 × 294 = P2 × 269.5

241.08 = 269.5P2

P2 = 241.08 ÷ 269.5

P2 = 0.895atm

Therefore, the pressure of the tyre after the temperature change is 0.89atm.

Learn more about pressure at: brainly.com/question/23358029

#SPJ4

6 0
2 years ago
a glass container was initially charged with 1.50 mol of a gas sample at 3.75 atm and 21.7C. some of the gas was release as the
butalik [34]

Answer:

0.39 mol

Explanation:

Considering the ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

At same volume, for two situations, the above equation can be written as:-

\frac {{n_1}\times {T_1}}{P_1}=\frac {{n_2}\times {T_2}}{P_2}

Given ,  

n₁ = 1.50 mol

n₂ = ?

P₁ = 3.75 atm

P₂ = 0.998 atm

T₁ = 21.7  ºC

T₂ = 28.1 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (21.7 + 273.15) K = 294.85 K  

T₂ = (28.1 + 273.15) K = 301.25 K  

Using above equation as:

\frac{{n_1}\times {T_1}}{P_1}=\frac{{n_2}\times {T_2}}{P_2}

\frac{{1.50\ mol}\times {294.85\ K }}{3.75\ atm}=\frac{{n_2}\times {301.25\ K  }}{0.998\ atm}

n_2=\frac{{1.50}\times {294.85}\times 0.998}{3.75\times 301.25}\ mol

Solving for n₂ , we get:

n₂ = 0.39 mol

7 0
3 years ago
There are 0.3 moles of xenon gas in a 0.5-liter container at 30 degrees C. What is the pressure exerted by the xenon gas
Kaylis [27]
PV = nRT
P = (nRT)/V
P = (0.3 mol × 0.08206 atm-l/(mol-K) × (273.15 + 30) K)/(0.5 l)
P = 14.9258934 atm
3 0
2 years ago
Read 2 more answers
Write the Henderson-Hasselbalch equation for a solution of formic acid. Calculate the quotient [HCO2]/[HCO2H] at (a) pH 3.000; (
Elena L [17]

Answer:

a. 0.182

b. 1.009

c. 1.819

Explanation:

Henderson-Hasselbach equation is:

pH = pKa + log [salt / acid]

Let's replace the formula by the given values.

a. 3 = 3.74 + log [salt / acid]

3 - 3.74 = log [salt / acid]

-0.74 = log [salt / acid]

10⁻⁰'⁷⁴ = 0.182

b. 3.744 = 3.74 + log [salt / acid]

3.744 - 3.74 = log [salt / acid]

0.004 = log [salt / acid]

10⁰'⁰⁰⁴ = 1.009

c. 4 = 3.74 + log [salt / acid]

4 - 3.74 = log [salt / acid]

0.26 = log [salt / acid]

10⁰'²⁶ = 1.819

3 0
3 years ago
Which planetary body was opportunity designed to explore?
11111nata11111 [884]
The rover was designed to explore A.Mars
3 0
3 years ago
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