The thing that they all have in common is that they all use electrical energy
Answer:
The energy for 1 mole of these photons is E = 31 ×
Explanation:
Given data
Wavelength
639.8 ×
m
Plank constant h = 6.626 ×
J sec
Speed of light c = 3 ×
meter per second
We know that Energy of a photon is given by

Value of ( h c ) = 6.626 ×
× 3 ×
= 19.878 × 
639.8 ×
m
Now Energy of a photon

E = 0.031 ×
Joule per mole
E = 31 ×
Therefore the energy for 1 mole of these photons is E = 31 ×
Answer: all I know it’s not -31.5 for ppl taking the k12 test
Explanation: I took the test
Explanation:
02 is the correct coefficient for hydrogen gas .
The questions you can answer are
1) what is the mass of one mole of raindrops?, and
2) How many moles of raindrops are in the pacific ocean
Solutions:
1) what is the mass of one mole of raindrops?
mass = number of rain drops * mass of on rain drop
The number of rain drops in one mole of rain drops is 6.02 * 10^23
So, the mass of one mole of rain drops is
6.02 * 10 ^ 23 rain drops * 50. mg * (1 kg / 1,000,000 mg) = 3.01 * 10^ 19 kg
The correct number of significant digits is 2, because 50. mg has two signficant digits, so the answer must be shown as 3.0 * 10^ 19 kg.
2) How many moles of raindrops are in the pacific ocean
Use the proportion 1 mol / 3.0 * 10^19 kg = x mol / 7.08 * 10^20 kg
And you solve for x:
x = (7.08 * 10^20 kg) * 1 mol / (3.0 * 10^19 kg) = 2.36 * 10 = 23.6 moles
Which rounded to two significant digits is 24 moles of rain drops.